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Quadratic Formula

This program computes all real and non-real (imaginary) roots/zeros for an equation using the quadratic formula.

Submitted By: SPlutard

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Views: 8,736

Language: C++

Last Modified: March 20, 2006

Instructions: This is a complete program, but feel free to eliminate/add to it in order to make it into a function for another program, or whatever is needed to fit your needs. It will work perfectly fine on its own, as well.

Snippet

// imaginary_Quad_Form.cpp : This program will compute all the roots/zeros of a quadratic equation (including imaginary ones).
//
#include "stdafx.h"
#include <iostream>
#include <math.h>
main()
{
float a, b, c, y1, y2, dis;
std::cout<<"This program will compute the roots/zeros of a quadratic equation (including imaginary ones).\n\n"<<"Please enter a, b, and c from the form: y = aX^2 + bX + c\n"<<"a = ";
std::cin>>a;
std::cout<<"b = ";
std::cin>>b;
std::cout<<"c = ";
std::cin>>c;
dis = ((b*b)-(4*a*c));
if(((b*b)-(4*a*c))<0)
{
dis = -1 * dis;
y1 = ((-1 * b) + (sqrt(dis)))/(2 * a);
y2 = ((-1 * b) - (sqrt(dis)))/(2 * a);
if(y1 == y2) std::cout<<"\a\nThe root is: "<<y1<<"i\n\n\n";
else std::cout<<"\a\nThe roots are: "<<y1<<"i and "<<y2<<"i\n\n\n";
}
else
{
y1 = ((-1 * b) + (sqrt(dis)))/(2 * a);
y2 = ((-1 * b) - (sqrt(dis)))/(2 * a);
if(y1 == y2) std::cout<<"\a\nThe root is: "<<y1<<"\n\n\n";
else std::cout<<"\a\nThe roots are: "<<y1<<" and "<<y2<<"\n\n\n";
}
system("Pause");
return 0;
}

Copy & Paste

// imaginary_Quad_Form.cpp : This program will compute all the roots/zeros of a quadratic equation (including imaginary ones).
//

#include "stdafx.h"
#include <iostream>
#include <math.h>

main()
{
     float a, b, c, y1, y2, dis;

std::cout<<"This program will compute the roots/zeros of a quadratic equation (including imaginary ones).\n\n"<<"Please enter a, b, and c from the form: y = aX^2 + bX + c\n"<<"a = ";
     std::cin>>a;
     std::cout<<"b = ";
     std::cin>>b;
     std::cout<<"c = ";
     std::cin>>c;
     dis = ((b*b)-(4*a*c));
     if(((b*b)-(4*a*c))<0)
     {
          dis = -1 * dis;
          y1 = ((-1 * b) + (sqrt(dis)))/(2 * a);
          y2 = ((-1 * b) - (sqrt(dis)))/(2 * a);
          if(y1 == y2) std::cout<<"\a\nThe root is: "<<y1<<"i\n\n\n";
          else std::cout<<"\a\nThe roots are: "<<y1<<"i and "<<y2<<"i\n\n\n";
     }
     else
     {
          y1 = ((-1 * b) + (sqrt(dis)))/(2 * a);
          y2 = ((-1 * b) - (sqrt(dis)))/(2 * a);
          if(y1 == y2) std::cout<<"\a\nThe root is: "<<y1<<"\n\n\n";
          else std::cout<<"\a\nThe roots are: "<<y1<<" and "<<y2<<"\n\n\n";
     }

system("Pause");
     return 0;
}