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Print Fibonacci series using do-while

Submitted By: eXceed69

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Views: 28,078

Language: C++

Last Modified: December 9, 2006

Snippet

#include <iostream>
int main()
{
//define first two fibonacci series numbers.
int fib1 = 0;
int fib2 = 1;
//declare the variable to store the next number of fibonacci series
int fib3;
//declare the variable to store how many numbers to be printed. Default is 2.
int numbers = 2;
//the counter to keep track how many numbers are printed.
int counter = 2;
//Ask user how many numbers of the fibonacci series need to be printed.
std::cout << "How many Fibonacci number you need ? : " ;
//Store the number.
std::cin >> numbers;
//If number entered is less than 3, exit the program.
if (numbers < 3) return 0;
//Print the first two element.
std::cout << fib1 << "\t" << fib2;
//do-while loop to calculate the new element of the series and printing the same.
do {
counter++;
fib3 = fib1 + fib2;
std::cout << "\t" << fib3;
fib1 = fib2;
fib2 = fib3;
} while (counter <= numbers);
std::cout << std::endl;
system("pause");
return 0;
}

Copy & Paste

#include <iostream>

int main()
{
     //define first two fibonacci series numbers.
    int fib1 = 0;
    int fib2 = 1;

//declare the variable to store the next number of fibonacci series
    int fib3;
    
     //declare the variable to store how many numbers to be printed. Default is 2.
     int numbers = 2;

//the counter to keep track how many numbers are printed.
     int counter = 2;
     
     //Ask user how many numbers of the fibonacci series need to be printed.
     std::cout << "How many Fibonacci number you need ? : " ;
     
    //Store the number.
    std::cin >> numbers;

//If number entered is less than 3, exit the program.
    if (numbers < 3) return 0;

//Print the first two element.
    std::cout << fib1 << "\t" << fib2;

//do-while loop to calculate the new element of the series and printing the same.
    do {
        counter++;
        fib3 = fib1 + fib2;
        std::cout << "\t" << fib3;
        fib1 = fib2;
        fib2 = fib3;    
    } while (counter <= numbers);
     
    std::cout << std::endl;
    system("pause");
     return 0;
}

Comments
mhero_04 2007-11-23 07:15:30
eow!! can u make a code for fibonacci series using for loop?? please..
nirvanarupali 2007-12-11 20:05:38
What happen if I enter 100?
JorisValencia 2008-09-01 06:58:35
why does this code have errors in my turbo c?
lorelie 2008-10-14 05:58:12
hi can you create a pr5ogram that generates N series of the fibonaccci nos. with MAX of 50 using an array,, please..
fa4han 2008-11-02 23:49:31
#include using namespace std; int main() { int fib1 = 0; int fib2 = 1; int fib3; cout
Migs 2008-11-24 14:06:03
Here is a simpler way and it deals with first two numbers:-Migs /* Given: n A non-negative integer. Task: To find the nth Fibonacci number. Return: This Fibonacci number in the function name. */ long fib(int n) { if ((n == 0) \|\| (n == 1)) // stopping cases return 1; else // recursive case return fib(n - 1) + fib(n - 2); }
kept2heart 2009-04-26 22:04:12
Thanks eXceed69 looking at your code helped me figure out what I did wrong in my code