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Logarithm calculation problems

Logarithm calculation problems

jcmaster2	7 Jun, 2009 - 09:28 PM Post #1
D.I.C Head Joined: 27 Apr, 2009 Posts: 139 Thanked: 4 times My Contributions	Kind of an offshoot of my previous post but this has to do with logarithmic properties Change of base: logbX = logaX/logaB and logb(X/Y ) = logbX - logbY and X/Y = X(1/Y) exponents here is the formula I have: logc (b / a) where c = 3, b = 88 , a = 3 how can I write b/a: Is it actually logc (logcb - logxa) or logc (X(1/Y) confused on how to proceed with the b/c- do I simpify that first then convert from base 5 to base 10 Insight would be appreciated...
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bsaunders	RE: Logarithm Calculation Problems 8 Jun, 2009 - 01:53 PM Post #2
D.I.C Addict Joined: 18 Jan, 2009 Posts: 554 Thanked: 42 times My Contributions	So are you trying to divide two logarithms of different bases?
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jcmaster2	RE: Logarithm Calculation Problems 12 Jun, 2009 - 06:08 AM Post #3
D.I.C Head Joined: 27 Apr, 2009 Posts: 139 Thanked: 4 times My Contributions	I fixed the other problems- These formulas- I have put together seem to work...Since, this place can really support the symbols I will use what I can Also, very detailed what the formulas are for..some basic clues for helping. 4 formulas different situations a, b, and c are integer and positive numbers... 1. value = ceiling((abs(b -a)) /c) 2. value = floor ((abs(b-a)) /c ) + 1 3. value= ceiling (abs (logb/logc- loga/logc)) when b no equal 0 other wise value = ceiling(abs(loga/logc)) 4. value= floor (abs (logb/logc- loga/logc)) + 1when b no equal 0 other wise value = floor(abs(loga/logc)) + 1 Anyway to simplify these formulas even further or OK...
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