Multiple Defenitions With Single Signiture In Webbrowser

Multiple Defenitions with single signiture in webbrowser ~PROJECT FOR FRIDAY URGENT HELP PLS~ Rate Topic:

#1 Jack Eagles1

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Posted 10 June 2009 - 02:45 AM

Hi, I have this code for some custom events in a webbrowser I'm making. The events are meant to be for when the user carries out certain actions, here are the actions:

Mouse Enters a link (HTMLElement)
Mouse Exits a link (HTMLElement)
Mouse Clicks a link (HTMLElement)

Mouse Enters an image (HTMLElement)
Mouse Exits an image (HTMLElement)

Here is the code:

  Private Sub nav() Handles Me.DocumentCompleted
	  Dim link As HtmlElement
		Dim links As HtmlElementCollection = Me.document.Links
		For Each link In links
			link.AttachEventHandler("onclick", AddressOf LinkClicked)
			link.AttachEventHandler("onmouseover", AddressOf onmouseenter)
			link.AttachEventHandler("onmouseleave", AddressOf onmouseleave)
		Next
		Dim picture As HtmlElement
		Dim pictures As HtmlElementCollection = Me.document.Images
		For Each picture In pictures
			picture.AttachEventHandler("mouseon", AddressOf onmouseenter)
			picture.AttachEventHandler("mouseon", AddressOf onmouseleave)
		Next
end sub

Here is the code to handle the link events:

  Private Sub onmouseenter(ByVal sender As Object, ByVal e As EventArgs)
		CType(Form1.TabControl1.SelectedTab.Controls.Item(0), WebBrowser).ContextMenuStrip = Form1.LinkContextMenu
	End Sub
	Private Sub onmouseleave(ByVal sender As Object, ByVal e As EventArgs)
		CType(Form1.TabControl1.SelectedTab.Controls.Item(0), WebBrowser).IsWebBrowserContextMenuEnabled = False
		CType(Form1.TabControl1.SelectedTab.Controls.Item(0), WebBrowser).ContextMenuStrip = Form1.MyContextMenu
	End Sub
	 Private Sub LinkClicked(ByVal sender As Object, ByVal e As EventArgs)
'complicated stuff which is irrelevant
   end sub

Here is the code to handle the Image events:

   Private Sub onmouseenter(ByVal sender As Object, ByVal e As EventArgs)
	   'Set a different context menu
	End Sub
   Private Sub onmouseleave(ByVal sender As Object, ByVal e As EventArgs)
	'Set a different context menu
	End Sub

Here is my problem: I have the event handler with the same name for both my Picture event and my Link events. How can I change my code so that the same function is carried out as I want, but the names for each of the events are different?

Here is the error which I am yielding:

Error	3	'Private Sub onmouseenter(sender As Object, e As System.EventArgs)' has multiple definitions with identical signatures.	C:\Users\Josh The Great\Documents\Visual Studio 2008\Projects\Net Browser\Net Browser\Forms\Form1.vb	2164	17	Net Browser

This post has been edited by Jack Eagles1: 10 June 2009 - 09:11 AM

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#2 Jack Eagles1

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Posted 10 June 2009 - 09:10 AM

Maybe no one has replied because I did not explain very well. I want to use the AttatchEventHandler class twice in the same class, using the same 'onclick' Function, but I get an error, because I have the same onclick function twice. Can anyone help pls?

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#3 RudiVisser

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Posted 10 June 2009 - 09:14 AM

I don't do VB, but your error seems fairly simple. If you're just having 2 functions, one for images and one for links, why not name them accordingly?

Asin, onmouseenter_Link/onmouseenter_Image. It doesn't matter what they're called to be assigned as an event handler.

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#4 modi123_1

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Posted 10 June 2009 - 09:36 AM

I'm not sure if I fully get what your issue is, but let me take a stab.

You have an action on this html element - a mouse click. You want it to do two different things depending on what it clicks, right? One for links and one for images, right? Are these two things being loaded into the same control? If so then have one event for the mouse click and in the event determine what you clicked.

Quote

object click event

if i clicked on a link then
do this
else if I clicked on an image then
do that
end if

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#5 Jack Eagles1

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Posted 10 June 2009 - 10:00 AM

Yeah, the problem is I cannot rename the functions, I have, but I'm not sure if it is impossible. If someone puts this code into vb.net, you will see what i mean. Thanks for any help in advance.

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