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HttpCookie Problem.

 

HttpCookie Problem.
cel09

3 Jul, 2009 - 08:14 AM
Post #1

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Joined: 3 Jul, 2009
Posts: 24
Hello, I'm new in this forum.

I want to make a web request with cookies.
This is my code:

CODE

HttpCookie cookie = new HttpCookie();
cookie.Value = "43546579";
Response.Cookies.Add(cookie);


Is this correct way to do this ? And I'm getting error: "The type or namespace name 'HttpCookie' could not be found". - Is System.Web incorrect ?

Thanks.

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PsychoCoder

RE: HttpCookie Problem.

3 Jul, 2009 - 08:19 AM
Post #2

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Yes the HttpCookie Class is part of the System.Web Namespace (not sure why you're getting this error). Have you added this to your class

CODE

using System.Web


To make a coookie should look something like this

CODE

HttpCookie cookie = new HttpCookie("YourCookieName");
cookie.Value = "43546579";
Response.Cookies.Add(cookie);
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cel09

RE: HttpCookie Problem.

3 Jul, 2009 - 08:42 AM
Post #3

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Yes, I have using System.Web, and I used:
CODE
HttpCookie cookie = new HttpCookie("YourCookieName");


But I'm still getting same error.
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JackOfAllTrades

RE: HttpCookie Problem.

3 Jul, 2009 - 02:19 PM
Post #4

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My Contributions
Have you added a reference to System.Web in your project?
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cel09

RE: HttpCookie Problem.

3 Jul, 2009 - 11:01 PM
Post #5

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QUOTE(JackOfAllTrades @ 3 Jul, 2009 - 02:19 PM) *

Have you added a reference to System.Web in your project?

Yes.
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cel09

RE: HttpCookie Problem.

5 Jul, 2009 - 12:38 PM
Post #6

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Posts: 24
I think I'm using it in wrong way... Can this be used in asp only ?

I want to make a simple webrequest:

CODE
HttpWebRequest request = (HttpWebRequest)WebRequest.Create("url");

            HttpWebResponse response;
            Stream dataStream;
            StreamReader reader;

          
                response = (HttpWebResponse)request.GetResponse();
                dataStream = response.GetResponseStream();
                reader = new StreamReader(dataStream);


Like this, and the page that I'm trying to connect checks if I have certain cookie, I want this cookie to be made available for that page.

Thanks.
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