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Calculating with x y.

Calculating with x y.

tom1597530	29 Oct, 2009 - 10:11 AM Post #1
New D.I.C Head Joined: 16 Oct, 2009 Posts: 13	Hello. I don't know how do you call it in English, but I need help with calculating x + x to be 2x. So, I have Command1, Text1 and Text2 and when I'll write in text1 etc. 3x + 4x and click Command1 it will show 7x in Text2. But When I'll write 3x+y+x, it will calculate 4x+y into the Text2. WHEN IT'S TOO COMPLICATED, THEN JUST HELP ME WITH x + x; y + y;.... THANX. I mean too complicated for you . THX
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vb5prgrmr	RE: Calculating With X Y. 29 Oct, 2009 - 07:21 PM Post #2
D.I.C Regular Joined: 21 Mar, 2009 Posts: 486 Thanked: 30 times My Contributions	Ahhh... a problem from the past... (Old teacher did this problem with an example of using a stack class...) Okay, you need to loop through the string looking for the operators (+-/) and testing for forced operator precidence (operations wrapped in parens). Then don't forget about natural operator precidence, & / before + & - (Left to right). So, in your example of 3x + y + x you would first search for forced operator precidence and do any calculations within the inner most set of parens... ((4x * 3x) + (12y * 2y)) - (6x + y) Then search for operators... (12x + 24y) - (6x + y) 6x + 23y (That is if I remember my math right...) Good Luck
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tom1597530	RE: Calculating With X Y. 30 Oct, 2009 - 07:59 AM Post #3
New D.I.C Head Joined: 16 Oct, 2009 Posts: 13	I don't get it. Why is 3x + y +x = 6x +23Y and not 4x + y??????????
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vb5prgrmr	RE: Calculating With X Y. 5 Nov, 2009 - 11:45 PM Post #4
D.I.C Regular Joined: 21 Mar, 2009 Posts: 486 Thanked: 30 times My Contributions	I switched from your example to my example and did not put enough lines between so you would know the difference...
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