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Assembly question

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Assembly question

kidworld	7 Feb, 2006 - 08:58 PM Post #1
New D.I.C Head Joined: 4 Nov, 2005 Posts: 4 My Contributions	mov [EAX+2EBX], CL EAX = 00001000h, EBX= 00002200h, DS = 1200h, SI = 0250h, CX= 0BADh, DX = 1FABh what is the addresses accessed ? and what's the different when I have mov [AX+2BX], CL, I am really confusing thanks
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born2c0de	12 Feb, 2006 - 04:47 AM Post #2
printf("I'm a %XR",195936478); Joined: 26 Nov, 2004 Posts: 3,905 Thanked 34 times Dream Kudos: 2800 Expert In: 80x86 Assembly, C/C++, VB6, VB.NET, C#, J2SE, Win32 API, Reversing My Contributions	It's simple. Here's what it actually means. CODE MOV [1000h + 4400h] , ADh This is so because The * Operator has higher precedence than the + operator CL refers to the lower byte of CX which is ADh The best way to see this work is by using a Debugger and watching the values of registers after this statement. That will help you understand this better. CODE mov [EAX+2EBX], CL mov [AX+2BX], CL Both of these are identical...the only difference being that the first one uses 32-bit Register Addressing while the latter uses 16-bit Register Addressing. The First one won't be accepted as a legal instruction on 16-bit Machines though.
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