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output of this code?

 
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output of this code?
duygugvn
post 28 Mar, 2006 - 01:28 PM
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CODE

#include<stdio.h>
int main(void)
{
    int num;
    printf("enter a num:");
    scanf("%d",&num);
    return 0;
}

double mean(void)
{
    int x=0,n=0;
    double mean=0;
    printf("enter the numbers,a minus value to stop\n");
    while(x>=0)
    {
 printf("x:");
 scanf("%d",&x);
 mean=mean+x;
 n++;
    }
    mean=mean/n;
    return mean;
}



I did not understand this code can you explain the aim of this code and this is not work!! crazy.gif

This post has been edited by Dark_Nexus: 29 Mar, 2006 - 09:13 AM
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Amadeus
post 28 Mar, 2006 - 02:19 PM
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g++ -o drink whiskey.cpp

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The purpose is to find the aritmetic mean of a set of numbers. It likely does not work because the fucntion itself is never called from the main function.
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duygugvn
post 29 Mar, 2006 - 07:52 AM
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QUOTE(Amadeus @ 28 Mar, 2006 - 02:11 PM)
The purpose is to find the aritmetic mean of a set of numbers. It likely does not work because the fucntion itself is never called from the main function.

the aritmetic mean ????what does it mean ???
I could not understand can you explain it for me by numerical valuess! sleepy.gif
and in main; not also in this functionI did not decide to place somewhere (function call)
where I write the function call and how I understand this generally???
can you give me sourcess which helps me !:huh:
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Amadeus
post 29 Mar, 2006 - 08:06 AM
Post #4


g++ -o drink whiskey.cpp

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Here is an explanation of the mean...it is often referred to as the average:
http://en.wikipedia.org/wiki/Arithmetic_mean
The general process is to add all the numbers you have been given, then divide the total amount by the number of numbers.

As for the function call itself, you can place it anywhere in the main function, (remove the scanf and prompt from the main function)...then set a value equal to the return value, and voila?
CODE

double mean;
mean = mean();
printf("%f",mean);
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