hello for all

I happy to be with you and deal with u

but I have question ... it is difficult

I hope anyone help me


Create a HugeInteger class that uses a 40 element array of digits to store integers as large as 40 digits each. Provide member functions input, output, add and subtract. For comparing HugeInteger objects, provide functions isEqualTo, isNotEqualTo, isGreaterThan, isLessThan, isGreaterThanOrEqualTo, isLessThanOrEqualTo these functions return true if the relationship holds between the two HugeIntegers and returns false if the relationship does not hold.

Write a menu-drive program that tests all the functionalities in this class.

The site has a policy by which we are more than happy to help users with their academic assignments, but we do require that some good faith effort is shown by the user. If you could please post the code you have written in an attempt to solve this assignment, we would be pleased to provide some guidance.

I can't read arry go on ( inside ) the object ,,,, and I don't know to use
overloding (> ,< ,!= ,== ) truthly .

but this is that i write and I can to arrive to it


here
#include<iostream>
#include<string>
#include<ctype.h>
using namespace std;
using std::istream;
using std::ostream;
class samp {
int n,m,o;
public:
samp (int i=0,int l=0,int j=0 )
{
n=i;
m=l;
o=j;
}

samp operator+(samp ob)
{
samp temp;
temp.n=n+ob.n;
temp.m=m+ob.m;
temp.o=o+ob.o;
return temp;
}

samp operator-(samp ob)
{
samp temp;
temp.n=n-ob.n;
temp.m=m-ob.m;
temp.o=o-ob.o;
return temp;
}
bool operator==(samp ob);

void print()
{
cout<<n<<" "<<m<<" "<<o<<"\n";
}
};
bool samp::operator ==(samp right)
{
if(n==right.n&&m==right.m&&o==right.o)
return true;
else
return false;
}



int main()
{
int choice;
samp A(1,2,3);
samp B(3,2,1);

cout<<"\n";

samp C;
while (choice!=2)
{
cout<<"what do you want to do..\n";
cout<<"1-Add two object..\n";
cout<<"2-Subtract two object..\n";
cout<<"3-com two object..\n";
cout<<"4-Exit..\n";
cout<<" SELECT" ;
cin>>choice;
switch(choice)
{
case 1:
C=A+B;
C.print();
break;
case 2:
C=A-B;
C.print();
break;
case 3:
A==B;
case 4:
break;
default:
cout<<" Invalid choice !\n";
}
cout<<endl<<"---------------------------------------------";
}

return 0;
}