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Multiplying with out "*" and LOOPS

 
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Multiplying with out "*" and LOOPS
jabez_jb
31 Aug, 2006 - 03:45 AM
Post #1

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Rewrite the following function so that the following conditions are satisfied:
a. The multiplication operator ('*') is not used.
b. The division operator ('/') is not used.
c. The function does not make use of loops.

CODE

int MultiplyBy321(int value)
{
int rslt;
rslt = value * 321;
return rslt;
}

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DeeViLiSh
RE: Multiplying With Out "*" And LOOPS
31 Aug, 2006 - 03:55 AM
Post #2

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Hmm is this an assignment or you're posting this for fun?
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jabez_jb
RE: Multiplying With Out "*" And LOOPS
31 Aug, 2006 - 03:56 AM
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no problem....i got the answer......but dunno the way is correct or not

CODE

int MultiplyBy321( int val )
{
  if( val == 1 )

  return 321;
  
   else
    return ( (MultiplyBy321(val-1)) +( 321));
}
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frog
RE: Multiplying With Out "*" And LOOPS
31 Aug, 2006 - 05:05 AM
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unleashed
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that works fine. i like thee ques though
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born2c0de
RE: Multiplying With Out "*" And LOOPS
31 Aug, 2006 - 05:27 AM
Post #5

printf("I'm a %XR",195936478);
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I think this Code better fits the bill.

This function can be used to multiply any number (since you can pass it as a parameter instead of hardcoding it) and has a sort of a cool-factor to it.
tongue.gif
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violent_crimson
RE: Multiplying With Out "*" And LOOPS
2 Sep, 2006 - 05:13 AM
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CODE

int MultiplyBy321( int val )
{
if( val == 1 )

return 321;

else
return ( (MultiplyBy321(val-1)) +( 321));
}


the function working because it returns itself is remarkable... great job you weird thinker O_o
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Dark_Nexus
RE: Multiplying With Out "*" And LOOPS
2 Sep, 2006 - 10:21 AM
Post #7

or something bad...real bad.
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it's called "recursion"
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