# include<iostream.h>
int main()
{
int ar[2]={8,2};        // (1)
int var1=66;            //(2)
int var2=111;           //(3)
int* ptarray[5];        //(4)
ptarray[0]= ar;          //(5)
ptarray[1]= &ar[1];  //Address of second element of array   ar //                  (5)
ptarray[2]= &var1;            //(6)
ptarray[3]= &var2;            //(7)
ptarray[4]= &ar[0];          //(8)
// To keep code small I use a loop          //(9)
for(int i=0;i<5;i++)
    cout<<*(ptarray[i])<<endl;    // (10)
}
CASE1:
OUTPUT 1:   8
                    2
                    6
                    11
                     8

CASE 2: IF i replace *(ptarray[i])  with    &(ptarray[i]) in LINE

NO 10 IN COUT statement  then output is

OUTPUT 2 :   0x 8fb8ffe4
                    0x 8fb8ffe6
                    0x 8fb8ffe8
                    0x 8fb8ffea
                    0x 8fb8ffec

CASE 3: IF I REPLACE *(ptarray[i])   with    (ptarray[i]) in LINE
               NO  10  THE OUT PUT IS
OUTPUT3:    
                   0x8fb8fff2
                   0x8fb8fff4
                   0x8fb8fff0
                   0x8fb8fffe
                   0x8fb8fff2
question :
                 what is the difference between  &ptarray[i]  &
                  ptarray[i]   due to that  the address location  of output 2   & output 3     is changing  .