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How to copy a Linked List

 
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How to copy a Linked List
sknox1
22 Oct, 2006 - 05:38 PM
Post #1

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CODE


#include<iostream>
#include<list>
#include "d_util.h"

using namespace std;











template <typename T>
void splice(list<T>& dest, list<T>::iterator pos,
                const list<T>& source)
{
    list<T>::const_iterator sourceIter;

    sourceIter = source.begin();


int a[] = {5, 8, 4, 1, 7};
int b[] = {12, 3, 15, 6, 23, 1, 2};
int sizeA= sizeof(a)/sizeof(int), sizeB= sizeof(B)/sizeof(int);

list<int>list1(a, a+sizeA);
list<int>list2(b, b+sizeB);



How do i copy list2 to the back of list1

edit: fixed [code] tags, modified title ~ jayman9
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gregoryH
RE: How To Copy A Linked List
23 Oct, 2006 - 12:22 AM
Post #2

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QUOTE(sknox1 @ 22 Oct, 2006 - 06:38 PM) *

CODE


#include<iostream>
#include<list>
#include "d_util.h"

using namespace std;











template <typename T>
void splice(list<T>& dest, list<T>::iterator pos,
                const list<T>& source)
{
    list<T>::const_iterator sourceIter;

    sourceIter = source.begin();


int a[] = {5, 8, 4, 1, 7};
int b[] = {12, 3, 15, 6, 23, 1, 2};
int sizeA= sizeof(a)/sizeof(int), sizeB= sizeof(B)/sizeof(int);

list<int>list1(a, a+sizeA);
list<int>list2(b, b+sizeB);



How do i copy list2 to the back of list1

edit: fixed [code] tags, modified title ~ jayman9

hi sk

Are you wishing to implement that using STL functionality (ie push() etc ) or roll your own?
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