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Function PointersIntroduction Function Pointers provide some extremely interesting, efficient and elegant programming
techniques. We can use them to replace switch/if statements, to realize our own late-binding or to
implement callbacks. Unfortunately probably due to their complicated syntax they are treated quite step
motherly in most computer books and documentations. If at all, they are addressed quite briefly. They
are less error prone than normal pointers cause we will never allocate or de-allocate memory with them.
All we’ve got to do is to understand what they are and to learn their syntax. But keep in mind:
It’s important to check whether we really need a function pointer. It’s nice to realize one’s own late-binding
but to use the existing structures of C++ may make our code more readable and clear.
What Is a Function Pointer ? Function Pointers are pointers, i.e. variables, which point to the address of a function. We must
keep in mind, that a running program gets a certain space in the main-memory. Both, the executable
compiled program code and the used variables, are put inside this memory. Thus a function in the program
code is, like e.g. a character field, nothing else than an address. It is only important how we, or better our
compiler/processor, interpret the memory a pointer points to.
How To Define a Function Pointer ? Since a function pointer is nothing else than a variable, it must be defined as usual.
Let’s take an example, we will define function pointers ptrToFunc, ptrToMember and
ptrToConstMember. The first is for C and will point to function which takes float and char as parameters and
returns integer.
Other Two are for C++ and will point to functions which takes float and char as parameters
and returns integer and are non-static members of class MyClass.
CODE
int (*ptrToFunc)(float, char) = NULL; // in C
int (MyClass::*ptrToMember)(float, char) = NULL; // C++
int (MyClass::*ptrToConstMember)(float, char) const = NULL; // C++
So in general we can say it is something like :
<return datatype of function> (* <pointer name>) (<parameters of function>);
[ It is a good practice to initialize function pointers with NULL. ]
How To Assign An Address to A Function Pointer ? It’s quite easy to assign the address of a function to a function pointer. Simply take the name of a
suitable and known function or member function. Although it’s optional for most compilers we should use the
address operator “&” in front of the function’s name in order to write portable code. We may have got to use
the complete name of the member function including class-name and scope-operator "::" [For C++]. Also we
have got to ensure, that we are allowed to access the function right in scope where our assignment stands.
CODE
// C
int SendIt (float a, char b)
{ printf("SendIt %f\n",a); return atoi(b); }
int SendIt2(float a, char b) const
{ printf("SendIt2 %f\n",a); return atoi(b); }
ptrToFunc = SendIt; // short form
ptrToFunc = &SendIt; // correct assignment using address operator
// C++
class MyClass
{
public:
int SendIt (float a, char b)
{ cout << "MyClass::SendIt "<<a<<endl; return atoi(b); }
int SendIt2(float a, char b)const
{ cout << "MyClass::SendIt2”<<a<<endl; return atoi(b); }
/* more code will follow*/
};
ptrToConstMember = &MyClass::SendIt2; // correct assignment using address
//operator
ptrToMember = &MyClass::SendIt;
// ptrToMember can also legally point to &MyClass::SendIt2
In C we call a function using a function pointer by explicitly dereferencing it using the * operator.
Alternatively we may also just use the function pointers instead of the function name. In C++ the two operators “.*”
and “->*” are used together with an instance of a class in order to call one of their (non-static) member functions. If
the call takes place within another member function we may use the “this” pointer.
CODE
int result1 = ptrToFunc(12, ’a’); // C short way
int result2 = (*ptrToFunc) (12, ’a’); // C
MyClass instance1= new MyClass;
int result3 = (instance1.*ptrToMember)(12, ’a’); // C++
//call from inside member function
int result4 = (*this.*ptrToMember)(12, ’a’); // C++ if this-pointer can be used
MyClass* instance2 = new MyClass;
int result4 = (instance2->*ptrToMember)(12, ’a’); // C++, instance2 is a pointer
How To Compare Function Pointers ? We can use the comparison-operators (==, !=) the same way as usual.
Following is the example of it.
CODE
// C
if(ptrToFunc >0) // check if initialized
if(ptrToFunc == &SendIt) //compare to check whether is points to SendIt
// C++
if(ptrToConstMember >0)
if(ptrToConstMember == &MyClass::SendIt2)
How to Pass a Function Pointer as an Argument ? We can pass a function pointer as a function’s calling argument. We need this many times
e.g. while passing a pointer to a callback function.
CODE
void PassPtr(int (*ptrToFunc)(float, char))
// This contains one parameter int (*ptrToFunc)(float,char) you can
// understand now what it is…
{
int result = (*ptrToFunc)(12, ’a’); // call using function pointer
cout << result << endl;
}
// execute code - ’SendIt’ is a suitable function as defined in above codes
void Pass_A_Function_Pointer()
{
PassPtr(&SendIt);
}
How to Return a Function Pointer ? It’s a little bit tricky but a function pointer can be a function’s return value. Here I am giving
two ways of how to return a pointer to a function which is taking two float arguments and returns a float.
If you want to return a pointer to a member function you have just got to change the definitions/declarations
of all function pointers.
CODE
// specifies which function to return
float (*GetPtr1(int a, int b))(float, float)
//here the function is GetPtr1(int,int) and it’s return parameter is a pointer to
//function
{
if(a>b)
return &Subtract;
else
return &Add;
}
//The easier way could be :
// Solution using a typedef : Define a pointer to a function which is taking
// two floats and returns a float
typedef float(*ptrToFunc)(float, float);
//now we can use ptrToFunc as user defined datatype, see following code :
ptrToFunc GetPtr2(int a, int b)
{
if(a>b)
return &Subtract;
else
return &Add;
}
void Return_A_Function_Pointer()
{
ptrToFunc pt2Function = NULL;
pt2Function=GetPtr1(10,20); // get function pointer from function ’GetPtr1’
cout << (*pt2Function)(2, 4) << endl; // call function using the pointer
pt2Function=GetPtr2(’10,20); // get function pointer from function ’GetPtr2’
cout << (*pt2Function)(2, 4) << endl; // call function using the pointer
}
Following program will make everything clear :
QUOTE
Please check program in document
How to Use Arrays of Function Pointers ? Operating with arrays of function pointer is very interesting. This offers the possibility to select
a function using an index. The syntax appears difficult, which frequently leads to confusion. There are two
ways of how to define and use an array of function pointers in C and C++. The first way uses a typedef, the
second way directly defines the array. It’s up to us which way we prefer.
CODE
// C
typedef int (*ptrToFunc)(float, char);
// illustrate how to work with an array of function pointers
void Array_Of_Function_Pointers()
{
// define arrays and initialise each element to NULL, <funcArr1> and <funcArr2> are arrays with 10 pointers to
//functions which return an int and take a float and a
//char
// first way using the typedef
ptrToFunc funcArr1[10] = {NULL};
// 2nd way directly defining the array
int (*funcArr2[10])(float, char) = {NULL};
// assign the function’s address
funcArr1[0] = &SendIt;
funcArr1[1] = &SendIt2;
/* more assignments */
// calling a function using an index to address the function pointer
printf("%d\n", funcArr1[1](12, ’a’)); // short form
printf("%d\n", (*funcArr1[0])(12, ’a’)); // "correct" way of calling
}
// C++
// type-definition:
typedef int (MyClass::*ptrToMember)(float, char);
void Array_Of_Member_Function_Pointers()
{
// arrays with 10 pointers to member functions which return an int and take
// a float and a char
// first way using the typedef
ptrToMember funcArr1[10] = {NULL};
// 2nd way of directly defining the array
int (MyClass::*funcArr2[10])(float, char) = {NULL};
// assign the function’s address - ’SendIt’ and ’SendIt2’
funcArr1[0] = funcArr2[1] = &TMyClass::SendIt;
funcArr1[1] = funcArr2[0] = &TMyClass::SendIt2;
// calling a function using an index to address the member function pointer
MyClass instance;
cout << (instance.*funcArr1[1])(12, ’a’) << endl;
cout << (instance.*funcArr1[0])(12, ’a’) << endl;
}
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Basics Of Function Pointers, What are function pointers and how to use them
9 Feb, 2007 - 03:57 AM
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