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Add ReplyI'm trying to open a text file.
My code is:
#include <stdio.h>
int main (void)
{
fopen(c:\numberarray.txt,r);
printf("File has been opened");
fclose;
printf("File has been closed");
}
It won't compile.
[C Language] Opening a text file.
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[C Language] Opening a text file.
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#1
bestbat
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Posted 24 February 2007 - 11:16 AM
I have done a search for this, most of the results were for C++ and I gave up after 6 pages.
I'm trying to open a text file.
My code is:
It won't compile.
I'm trying to open a text file.
My code is:
It won't compile.
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#2
Craige
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Posted 24 February 2007 - 11:51 AM
fopen("file", "a");
a can be a range of values, each standing for how to open the file. a is append, r is read. I don't know all the values off the top of my head. You'll have to google for them.
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#3
horace
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Posted 24 February 2007 - 12:10 PM
in addition to enclosing the file name and mode in " (as indicated by Craige) you need to enter \ as \\ in a string specifing a filename, e.g.
i.e. in "c:\numberarray.txt" the \n would be the newline character whereas in c:\\numberarray.txt" the \\ is the \ character
fopen("c:\\numberarray.txt","r");
i.e. in "c:\numberarray.txt" the \n would be the newline character whereas in c:\\numberarray.txt" the \\ is the \ character
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#4
IainMackay85
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Posted 24 February 2007 - 12:11 PM
you need to put quote marks round your file name or the compiler won't treat it as a string.
also you haven't declared r
is this the first c program you have done?
its either that or *FILE r i can't remember.
fopen("c:\numberarray.txt",r);
also you haven't declared r
FILE *r
is this the first c program you have done?
#include <stdio.h>
int main (void)
{
FILE *r
fopen("c:\numberarray.txt",r);
printf("File has been opened");
fclose;
printf("File has been closed");
}
its either that or *FILE r i can't remember.
bestbat, on 24 Feb, 2007 - 12:16 PM, said:
I have done a search for this, most of the results were for C++ and I gave up after 6 pages.
I'm trying to open a text file.
My code is:
It won't compile.
I'm trying to open a text file.
My code is:
#include <stdio.h>
int main (void)
{
fopen(c:\numberarray.txt,r);
printf("File has been opened");
fclose;
printf("File has been closed");
}
It won't compile.
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0
#6
bestbat
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Posted 24 February 2007 - 12:45 PM
Thanks all of you.
@ IainMackay85
No this is not my first C program, I didnt think i needed to declare r as i'm using it to tell fopen that I want to read the file.
@jayman thanks for the link, i'll go through it and post back my results.
@ IainMackay85
No this is not my first C program, I didnt think i needed to declare r as i'm using it to tell fopen that I want to read the file.
@jayman thanks for the link, i'll go through it and post back my results.
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#7
Amadeus
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Posted 24 February 2007 - 07:56 PM
IainMackay85, on 24 Feb, 2007 - 03:11 PM, said:
you need to put quote marks round your file name or the compiler won't treat it as a string.
also you haven't declared r
is this the first c program you have done?
fopen("c:\numberarray.txt",r);
also you haven't declared r
FILE *r
is this the first c program you have done?
Not sure of the reason for that question, especially given your answer.
One does not need to declare r - it needs to be enclosed in quotes. It is not a pointer to a file, it is a mode that indicates the file is to be read. You are likely thinking of a file pointer that is declared to allow the program to keep rack of the file being accessed, such as
FILE *r;
r = fopen("c:\numberarray.txt","r");
bestbat, you were correct in your assumptions about the mode identifier, it does not need to be declared. It does need to be in quotes, however.
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