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[C Language] Opening a text file.

 
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[C Language] Opening a text file.
bestbat
post 24 Feb, 2007 - 12:16 PM
Post #1


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I have done a search for this, most of the results were for C++ and I gave up after 6 pages.

I'm trying to open a text file.

My code is:
CODE

#include <stdio.h>


int main (void)
{
fopen(c:\numberarray.txt,r);
printf("File has been opened");
fclose;
printf("File has been closed");
}


It won't compile.
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Craige
post 24 Feb, 2007 - 12:51 PM
Post #2


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CODE

fopen("file", "a");


a can be a range of values, each standing for how to open the file. a is append, r is read. I don't know all the values off the top of my head. You'll have to google for them.
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horace
post 24 Feb, 2007 - 01:10 PM
Post #3


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in addition to enclosing the file name and mode in " (as indicated by Craige) you need to enter \ as \\ in a string specifing a filename, e.g.
CODE

fopen("c:\\numberarray.txt","r");

i.e. in "c:\numberarray.txt" the \n would be the newline character whereas in c:\\numberarray.txt" the \\ is the \ character
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IainMackay85
post 24 Feb, 2007 - 01:11 PM
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you need to put quote marks round your file name or the compiler won't treat it as a string.
CODE

fopen("c:\numberarray.txt",r);


also you haven't declared r

CODE

FILE *r


is this the first c program you have done?

CODE

#include <stdio.h>


int main (void)
{
FILE *r
fopen("c:\numberarray.txt",r);
printf("File has been opened");
fclose;
printf("File has been closed");
}


its either that or *FILE r i can't remember.


QUOTE(bestbat @ 24 Feb, 2007 - 12:16 PM) *

I have done a search for this, most of the results were for C++ and I gave up after 6 pages.

I'm trying to open a text file.

My code is:
CODE

#include <stdio.h>


int main (void)
{
fopen(c:\numberarray.txt,r);
printf("File has been opened");
fclose;
printf("File has been closed");
}


It won't compile.
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jayman9
post 24 Feb, 2007 - 01:11 PM
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Joined: 26 Dec, 2005
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You can find a tutorial here that will explain all the necessary steps.
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bestbat
post 24 Feb, 2007 - 01:45 PM
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Thanks all of you.

@ IainMackay85
No this is not my first C program, I didnt think i needed to declare r as i'm using it to tell fopen that I want to read the file.

@jayman thanks for the link, i'll go through it and post back my results.
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Amadeus
post 24 Feb, 2007 - 08:56 PM
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g++ -o drink whiskey.cpp

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QUOTE(IainMackay85 @ 24 Feb, 2007 - 03:11 PM) *

you need to put quote marks round your file name or the compiler won't treat it as a string.
CODE

fopen("c:\numberarray.txt",r);


also you haven't declared r

CODE

FILE *r


is this the first c program you have done?


Not sure of the reason for that question, especially given your answer.

One does not need to declare r - it needs to be enclosed in quotes. It is not a pointer to a file, it is a mode that indicates the file is to be read. You are likely thinking of a file pointer that is declared to allow the program to keep rack of the file being accessed, such as
CODE

FILE *r;
r = fopen("c:\numberarray.txt","r");

bestbat, you were correct in your assumptions about the mode identifier, it does not need to be declared. It does need to be in quotes, however.
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bestbat
post 25 Feb, 2007 - 07:46 PM
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Thanks everyone, I now have a better understanding of opening and closing files.
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