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Accesing a an array of an array of characters

 
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Accesing a an array of an array of characters
Pontus
9 Apr, 2007 - 10:31 AM
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i've made a array of an array of chars
CODE

char knoptext [][30];

now how do i get in knoptext[][1] the word "test"
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BitByte
RE: Accesing A An Array Of An Array Of Characters
9 Apr, 2007 - 10:44 AM
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CODE
knoptext[][1] = "test"
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Pontus
RE: Accesing A An Array Of An Array Of Characters
9 Apr, 2007 - 11:10 AM
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QUOTE(BitByte @ 9 Apr, 2007 - 11:44 AM) *

CODE
knoptext[][1] = "test"


then my compiler gives the error : main.cpp expected primary-expression before ']' token
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BitByte
RE: Accesing A An Array Of An Array Of Characters
9 Apr, 2007 - 11:35 AM
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CODE
int rows = 5;
char *myArray[rows][30];

myArray[1][30] = "test";
myArray[2][30] = "another test";

std::cout << myArray[1][30] << std::endl;
std::cout << myArray[2][30] << std::endl;


I hope i don't get into trouble for that. myArray ( or whatever yours is called ) needs to be a pointer to each row of the array. The 30 is the length of each array.
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CPlusPlusNewbie
RE: Accesing A An Array Of An Array Of Characters
9 Apr, 2007 - 10:21 PM
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QUOTE(manhaeve5 @ 9 Apr, 2007 - 12:10 PM) *

QUOTE(BitByte @ 9 Apr, 2007 - 11:44 AM) *

CODE
knoptext[][1] = "test"


then my compiler gives the error : main.cpp expected primary-expression before ']' token


your error may be that you forgot the semicolon at the end of your code. sorry, im new here just reading some posts. i hope i haven't over stepped my boundaries.
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Pontus
RE: Accesing A An Array Of An Array Of Characters
10 Apr, 2007 - 12:20 AM
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QUOTE(BitByte @ 9 Apr, 2007 - 12:35 PM) *

CODE
int rows = 5;
char *myArray[rows][30];

myArray[1][30] = "test";
myArray[2][30] = "another test";

std::cout << myArray[1][30] << std::endl;
std::cout << myArray[2][30] << std::endl;


I hope i don't get into trouble for that. myArray ( or whatever yours is called ) needs to be a pointer to each row of the array. The 30 is the length of each array.

then it only displayes the chars 't' and 'a'
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CPlusPlusNewbie
RE: Accesing A An Array Of An Array Of Characters
10 Apr, 2007 - 12:47 AM
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QUOTE(BitByte @ 9 Apr, 2007 - 12:35 PM) *

CODE
int rows = 5;
char *myArray[rows][30];

myArray[1][30] = "test";
myArray[2][30] = "another test";

std::cout << myArray[1][30] << std::endl;
std::cout << myArray[2][30] << std::endl;


I hope i don't get into trouble for that. myArray ( or whatever yours is called ) needs to be a pointer to each row of the array. The 30 is the length of each array.



30 is not the length of each array. it is the column location 29. if you are working with two dimensional arrays, you are working with row column format. to declare a char array with the length of 30 you would simply declare a an array like this: char myArray[30];

even better: declare a constant length such as: const int MAX_LEN = 30;
...
...
..
char myArray[MAX_LEN];

cin >> myArray; // where myArray = test;

cout << myArray; //output would be test;

This post has been edited by CPlusPlusNewbie: 10 Apr, 2007 - 01:41 AM
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CPlusPlusNewbie
RE: Accesing A An Array Of An Array Of Characters
10 Apr, 2007 - 02:26 AM
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oops.

This post has been edited by CPlusPlusNewbie: 10 Apr, 2007 - 02:28 AM
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BitByte
RE: Accesing A An Array Of An Array Of Characters
10 Apr, 2007 - 03:00 AM
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Oop from me aswell, it did actually work though. I had -Wall and -pedantic turned off on the compiler.

CODE
#include <iostream>

int main()
{
   const int rows = 5;
   char *myArray[rows];

   myArray[0] = "test";
   myArray[1] = "another test";

   std::cout << myArray[0] << std::endl;
   std::cout << myArray[1] << std::endl;

   return 0;
}



One of the reasons the C++ string class is easier to work with. My apologies for any inconvenience.


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NickDMax
RE: Accesing A An Array Of An Array Of Characters
10 Apr, 2007 - 08:12 PM
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QUOTE
I had -Wall and -pedantic turned off on the compiler.

LOL!!! I do that too!

In a multi-dimentional array in C/C++ you can think of it as a pointer of type char[Max String Length], so if I wanted to make an array of 30 byte strings:

CODE

char Array[][30] = {"zero", "one", "two", "three"};
cout << Array[0] << '\t' << Array[1] << '\t' <<Array[2] << '\t' <<Array[3];


Now if I wanted to access a particular character in one of these strings:

Array[0][1]='o'; <-- makes "zero" into "zoro"
Array[1][2]=0; <-- makes "one" into "on" (zero terminated strings)
Array[2][0]='b';Array[2][1]='o'; <-- makes "two" into "boo"
Array[3][5]='D';Array[3][6]=0; <-- makes "three" into "threeD"
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