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Unix Shell Script question

 
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Unix Shell Script question
Emper0r
4 May, 2007 - 09:39 AM
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I'm trying to write a shell script tha takes a dir name and a file extention from the user, for example:

~/mydir txt

and returns the absolute pathname and filename and the specific permissions of that certain file, for example:

/home/me/mydir/test.txt -rw-r--r--

I'm very new to making shell scripts, here's what I have so far:

for fileName in `find $1 -name '*'.$2`
do
echo $fileName
done

This returns the absolute path with the filename but I have no idea how to return the permissions on the file. How would I achieve this? Thanks to anyone for help.
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Nova Dragoon
RE: Unix Shell Script Question
4 May, 2007 - 10:23 AM
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The ls command in long format "ls -l" shows file permissions as the first column, you could use cut to extract just that column and print it


ls -l filename | cut -f1 -d" "
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Emper0r
RE: Unix Shell Script Question
6 May, 2007 - 09:00 PM
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QUOTE(Nova Dragoon @ 4 May, 2007 - 11:23 AM) *

The ls command in long format "ls -l" shows file permissions as the first column, you could use cut to extract just that column and print it


ls -l filename | cut -f1 -d" "


Thanks but is there any way to do it via pathname expansion?

Like ls-l filename | awk {print == $1} or something?
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