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function inside a switch

 
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function inside a switch
Ragnarok
14 May, 2007 - 07:13 PM
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Can a function be called inside a switch/case in the main()
for example
CODE

#include<iostream>
#include <cctype>
#include <string>

using namespace std;

int main()
{
    char ch = 0;

    cout<<"\nCheck In(I)";
    cout<<"\nCheck Out(O)";
    cout<<"\nStatus(S)";
    cout<<"\nQuit(Q)";
    cout<<endl;
    cin >> ch;

    switch(ch)
    {
        case 'i': case 'I':
            cout << checkin()<<endl;
            break;


where the checkin is the name of the function.

This post has been edited by Ragnarok: 14 May, 2007 - 07:14 PM
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AmitTheInfinity
RE: Function Inside A Switch
14 May, 2007 - 11:04 PM
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why not? you can do that for sure.
But make sure that if your variable used for switch is global then these called functions should not modify that variable.

and whenever you are writing fallthrough switches like that, make sure that you write them on new line.
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Ragnarok
RE: Function Inside A Switch
15 May, 2007 - 04:31 AM
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QUOTE(AmitTheInfinity @ 15 May, 2007 - 12:04 AM) *

why not? you can do that for sure.
But make sure that if your variable used for switch is global then these called functions should not modify that variable.

and whenever you are writing fallthrough switches like that, make sure that you write them on new line.



but why I got error when compiling that checkin is undeclare. The function checkin is outside of the main.


EDIT- I got it I just need to put the funtion on top of the main.

but do you know what this error mean( warning: the address of `int checkin(int*, int&)', will always evaluate as `true')

This post has been edited by Ragnarok: 15 May, 2007 - 04:56 AM
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