Here is my code to return a pointer-array-thingie


Now how cane i make this work with this?:

Any help is appreciated

char *phrase = convert(b);

But it must be used like this:

not

#1 Why "must it be used" like that?

You see the two things are relativity different to the compiler. Yes a char[] and a char * are very similar, but a char[] is a non-dynamic allocated array. Its size must be known by the compiler so that it knows how much room to set aside on the stack. The notation:
char Array[] = "This is a test";
is an initialization line. Where the compiler determines how much space is needed and sets it aside.

Your program creates a dynamic array (though why you limited yourself to 100 chars I don't know) and then copies the contents of a string into this array. Unless you want a memory leak, you will have to return that pointer, so that later you can use delete to destroy the array when it is no longer needed.

There might be some way to overload either the assignment or [] operator to let this work... but I doubt it.

There are other approaches.

You realize that this is cyclic though right?

By calling convert("hello"); you are forcing the compiler to change a string literal (const char *) into a string, which you then convert back to a c-string... Why not just say char hello[] = "world";? skip the middle man.

...so why must it work like this?

ok, ill do it that way, thx