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k0b13r
post 14 Aug, 2007 - 05:26 PM
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Hi. I wanted to load every file in specified directory to array ( via file(); ). How can I "jump" over all files without specifing their names ? Thanks for answer
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snoj
post 14 Aug, 2007 - 05:36 PM
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file() doesn't work that way.

Come back when you know what you're doing.

[edit] my apologies for the above comment, it was uncalled for.
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no2pencil
post 14 Aug, 2007 - 05:40 PM
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Run a dir listing, get all the files, & load each of them inside of a for statement.

CODE

function read_dir($dir) {
   $dir_Array=array();
   $path = opendir($dir);
   while (false !== ($file = readdir($path))) {
        if(is_file($dir."/".$file)) $files[]=$file;
        else  $dirs[]=$dir."/".$file;
   }
   if($dirs) {
       natcasesort($dirs);
       foreach($dirs as $dir) {
           //echo $dir;
           read_dir($dir);
       }
   }
   if($files) {
     array_push($dir_Array,$files);
     $_i=0;
     natcasesort($files);
     foreach ($files as $file) {
       // load them here...
     }
  }
}

Soooomething similar to this. This code was pulled from one of my sites that pulls a dir listing.

Good luck!
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k0b13r
post 14 Aug, 2007 - 05:42 PM
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I can put file content into array via file, but I have to specify file name. I want to put contents of each file like this, but I want to script take file names by itself automatically, if You understand what I mean ... biggrin.gif Is it possible ?

Thanks no2pencil, I will take a look of this smile.gif

This post has been edited by k0b13r: 14 Aug, 2007 - 05:43 PM
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no2pencil
post 14 Aug, 2007 - 05:51 PM
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QUOTE(k0b13r @ 14 Aug, 2007 - 06:42 PM) *

I can put file content into array via file, but I have to specify file name.

The code I supplied will run on ANY file in a directory, you do not have to referance each file. Simply say WHICH directory you want to load every file from.

QUOTE(k0b13r @ 14 Aug, 2007 - 06:42 PM) *

Thanks no2pencil, I will take a look of this smile.gif


Good luck.
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