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Assembly Code Equation Help

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Assembly Code Equation Help

tinytoh	23 Sep, 2007 - 04:12 PM Post #1
New D.I.C Head Joined: 9 Apr, 2007 Posts: 11 My Contributions	I need some help writing the .data and .code portions of the code to implement the following equation: X=(10Y-3Z)/5 with X, Y=2, Z=5 I have most of it I think but I do not know where to go from here?? CODE .DATA X DW ? Y DW 2 Z DW 5 .CODE mov ax,@data mov ds,ax mov dx,ah mul Y mov bx,03h mul Z sub ax,bx cwd div This is where I got stuck....If someone could help me out I would really appreciate it Thanks! This post has been edited by tinytoh: 23 Sep, 2007 - 04:14 PM
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William_Wilson	RE: Assembly Code Equation Help 23 Sep, 2007 - 05:14 PM Post #2
lost in compilation Joined: 23 Dec, 2005 Posts: 4,101 Thanked: 25 times Dream Kudos: 3275 Expert In: Java, C, Javascript My Contributions	http://www.dreamincode.net/code/snippet446.htm this snippet is a division example for 32 bit numbers, i think it should help. it also shows which registers hold the numerator and where the quotient and remainder end up
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tinytoh	RE: Assembly Code Equation Help 23 Sep, 2007 - 05:27 PM Post #3
New D.I.C Head Joined: 9 Apr, 2007 Posts: 11 My Contributions	that helps a little, however, I'm still not sure how to divide the stored values in both the ax and bx? I do not think that you can divide ax by bx
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born2c0de	RE: Assembly Code Equation Help 23 Sep, 2007 - 11:23 PM Post #4
printf("I'm a %XR",195936478); Joined: 26 Nov, 2004 Posts: 4,026 Thanked: 38 times Dream Kudos: 2800 Expert In: 80x86 Assembly, C/C++, VB6, VB.NET, C#, J2SE, Win32 API, Reversing My Contributions	QUOTE I do not think that you can divide ax by bx Of course you can. CODE div bx
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