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Square grid

 
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Square grid, looping problems
burfy1982
17 Dec, 2007 - 05:56 AM
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I am trying to write a program with a loop in a loop, to plot X/Y coordinates for a 5 by 5 grid but i can't get the looping correct, can anyone help me?
#include <stdio.h>
#include <conio.h>
void main ()
{
int x, y;
clrscr ();

for (x=0; x<=5; x++)
{
for (y=0; y<=5; y++)
{
printf ("\t%d",x);
printf ("\t%d",y);
}
printf (" \n");

}
getch ();
}
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baavgai
RE: Square Grid
17 Dec, 2007 - 06:24 AM
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Sort of close. Think about what you're doing. You want to print out y lines, x length. Your inner loop does the x length part.

CODE

#include <stdio.h>
int main () {
    int x, y;
    
    for (y=0; y<5; y++) {
        // you're at the start of your line
        // put the tab here
        printf ("\t");
        // if you like, make a note that this is y line
        printf ("%d: ",y);
        for (x=0; x<5; x++) {
            printf ("%d",x);
        }
        // we're drawn our line, end it
        printf("\n");
    }
}


Hope this helps.

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burfy1982
RE: Square Grid
17 Dec, 2007 - 06:46 AM
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Thanks for your reply,but i am trying to write this program so that i am able to print on the screen like this: 0,0 0,1 0,2 etc
1,0 1,1 1,2 etc
2,0 2,1 2,2 etc

So its a 5 by 5 grid with 25 elements.
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baavgai
RE: Square Grid
17 Dec, 2007 - 07:17 AM
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Still not following. This
CODE

#include <stdio.h>
int main () {
    int x, y;
    for (y=0; y<5; y++) {
        for (x=0; x<5; x++) {
            printf ("(%d,%d),",x,y);
        }
        printf("\n");
    }
}


Produces this:
CODE

(0,0),(1,0),(2,0),(3,0),(4,0),
(0,1),(1,1),(2,1),(3,1),(4,1),
(0,2),(1,2),(2,2),(3,2),(4,2),
(0,3),(1,3),(2,3),(3,3),(4,3),
(0,4),(1,4),(2,4),(3,4),(4,4),


Which is, um, 25 elements?

If you want to replace printf ("(%d,%d),",x,y); with printf ("X"); you get this:
CODE

XXXXX
XXXXX
XXXXX
XXXXX
XXXXX


Which is a happy little square. I guess I don't understand your expectations of square, sorry.
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burfy1982
RE: Square Grid
17 Dec, 2007 - 07:33 AM
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No thanks for your help i am trying to learn C on my own, so every little bit of help is greatful.
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