This program works fine with one exception, if the user enters more than one character, I would like the invalid user entry message to show. It does this if anything other than a letter is entered but will not if the user enters two or more letters - the first letter is picked up and the proper alpha is displayed. This isn't real important, I just want to know how I can make this a little cleaner.
CODE
//Write a C++ program that inputs a letter and outputs the corresponding
//International Civil Aviation Organization alphabet word using functional
//decomposition.
#include <iostream>
#include <string>
using namespace std;
int main()
{
cout<<"\t\tInternational Civil Aviation Organization Alphabet\n";
//declare variables
char letter; //store user input
char choice; //store user choice to continue using program or exit the program.
do //start do loop for user multiple entries
{
//instructions for user input
cout<<"Please enter a letter, (A thru Z), that you would like to convert"<< endl;
cout<<"to an International Civil Aviation Organization alphabet word"<< endl;
cout<<"and press enter\t"<<endl;
cout<<"\n\n\t";
cin>> letter; //user input
cout<<"\n\n";
if (letter == 'A' || letter == 'a')
cout<<"\nThe alphabet word is: Alpha"<< endl;
else
if (letter == 'B' || letter == 'b')
cout<<"\nThe alphabet word is: Beta"<< endl;
else
if (letter == 'C' || letter == 'c')
cout<<"\nThe alphabet word is: Charlie"<< endl;
else
if (letter == 'D' || letter == 'd')
cout<<"\nThe alphabet word is: Delta"<< endl;
else
if (letter == 'E' || letter == 'e')
cout<<"\nThe alphabet word is: Echo"<< endl;
else
if (letter == 'F' || letter == 'f')
cout<<"\nThe alphabet word is: Foxtrot"<< endl;
else
if (letter == 'G' || letter == 'g')
cout<<"\nThe alphabet word is: Golf"<< endl;
else
if (letter == 'H' || letter == 'h')
cout<<"\nThe alphabet word is: Hotel"<< endl;
else
if (letter == 'I' || letter == 'i')
cout<<"\nThe alphabet word is: India"<< endl;
else
if (letter == 'J' || letter == 'j')
cout<<"\nThe alphabet word is: Juliet"<< endl;
else
if (letter == 'K' || letter == 'k')
cout<<"\nThe alphabet word is: Kilo"<< endl;
else
if (letter == 'L' || letter == 'l')
cout<<"\nThe alphabet word is: Lima"<< endl;
else
if (letter == 'M' || letter == 'm')
cout<<"\nThe alphabet word is: Mike"<< endl;
else
if (letter == 'N' || letter == 'n')
cout<<"\nThe alphabet word is: November"<< endl;
else
if (letter == 'O' || letter == 'o')
cout<<"\nThe alphabet word is: Oscar"<< endl;
else
if (letter == 'P' || letter == 'p')
cout<<"\nThe alphabet word is: Papa"<< endl;
else
if (letter == 'Q' || letter == 'q')
cout<<"\nThe alphabet word is: Quebec"<< endl;
else
if (letter == 'R' || letter == 'r')
cout<<"\nThe alphabet word is: Romeo"<< endl;
else
if (letter == 'S' || letter == 's')
cout<<"\nThe alphabet word is: Sierra"<< endl;
else
if (letter == 'T' || letter == 't')
cout<<"\nThe alphabet word is: Tango"<< endl;
else
if (letter == 'U' || letter == 'u')
cout<<"\nThe alphabet word is: Uniform"<< endl;
else
if (letter == 'V' || letter == 'v')
cout<<"\nThe alphabet word is: Victor"<< endl;
else
if (letter == 'W' || letter == 'w')
cout<<"\nThe alphabet word is: Whiskey"<< endl;
else
if (letter == 'X' || letter == 'x')
cout<<"\nThe alphabet word is: X-Ray"<< endl;
else
if (letter == 'Y' || letter == 'y')
cout<<"\nThe alphabet word is: Yankee"<< endl;
else
if (letter == 'Z' || letter == 'z')
cout<<"\nThe alphabet word is: Zulu"<< endl;
else
cout<<"Invalid entry. Please enter one letter, A thru Z"<< endl;
//endif;
cout<<"\n\nWould you like to enter another letter? (Y/N)\t";
cin>> choice;
cout<<"\n\n";
}while (choice == 'Y' || choice == 'y');
cout<<"\n\nThank you for trying my program\n\n";
return 0;
}