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converting 32 bit integers

 
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converting 32 bit integers
tootypegs
post 27 Jan, 2008 - 10:55 AM
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Hi, i have the following hex string 'C4 48 FD FF'. When using a calulator to convert it i do not get the value im after. The number im after converting it to is '-177980'. I think this is in 32 bit interger format??? anyway im not sure i understand how that is possible but my hex editor gives me that value from that hex string in the 32 bit data interpretor. Can anyone explain to me how this is converted? And is this possible to do in c++?

This post has been edited by tootypegs: 27 Jan, 2008 - 11:39 AM
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Martyr2
post 27 Jan, 2008 - 11:49 AM
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hehe... its backwards. If you calculate 5357268 to hex you get 00 51 BE D4. So either your hex converter is going backwards or some other conversion is running the wrong way for you. Check that out and let us know if you have found out what is going on.

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tootypegs
post 27 Jan, 2008 - 12:51 PM
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QUOTE(Martyr2 @ 27 Jan, 2008 - 12:49 PM) *

hehe... its backwards. If you calculate 5357268 to hex you get 00 51 BE D4. So either your hex converter is going backwards or some other conversion is running the wrong way for you. Check that out and let us know if you have found out what is going on.

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hey thank you, my fault tho i put the wrong example up for post. the example i should have included was 'C4 48 FD FF' to '-177980'.

i just can't understand how this can happen?
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tootypegs
post 28 Jan, 2008 - 08:02 AM
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AH!! i think ive cracked it but im not too sure how to code it in c++. First i hav the hex string 'C4 48 FD FF'. I have to convert to little endien format 'FF FD 48 C8' and convert to decimal. Then convert the decimal to binary so i get
'11111111111111010100100011000100'. Then i need to reverse the bits so that '1's' become '0's' and '0's' become '1's'. Then i convert that back to decimal and add 1. Is there an easy way to do this to a number in c++?


thanks
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