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How do I print a variable name?

 
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How do I print a variable name?
dls76
10 Mar, 2008 - 03:51 PM
Post #1

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I know this is a crazy question! We are having to make a test and then figure the grade and display the questions that were missed. I have it all working but it isn't displaying one of the questions right when it is missed. I haven't been able to figure out how to get it to display correctly. I have tried double quotes and single quotes. The original question is: The statement "5 = $variable" will ---and then the user choses an answer.

Thank you for your help!

CODE

echo
    "3. The statement '5 = $variable' will
    <br />
     A. compare $variable to 5
     <br />
     B. set $variable to 5
     <br />
     <b>C. result in an error</b>
     <br />
     D. none of the above
     <br />
    <br />";
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spearfish
RE: How Do I Print A Variable Name?
10 Mar, 2008 - 04:59 PM
Post #2

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QUOTE(dls76 @ 10 Mar, 2008 - 04:51 PM) *

CODE

echo
    "3. The statement '5 = $variable' will



That's your problem right there. Are you getting a parse error? Because it's likely that PHP is trying to:
CODE

echo $variable'


Your question was ambiguous as to what you are trying to do. If you want it to echo the variable, you need to separate it from the apostrophe like this:
CODE

echo "{$variable}'"


Remember variables in double quotes will expand, but not if PHP is looking for the wrong variable!

Another thing you might be trying to do is have it literally type "$variable", in which case you need to escape the dollar sign like this:
CODE

echo "\$variable"


Hope I helped, and feel free to correct me.
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dls76
RE: How Do I Print A Variable Name?
10 Mar, 2008 - 05:19 PM
Post #3

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Joined: 15 Feb, 2008
Posts: 18
I wanted it to literally print $variable. That helped, I got it to work. Thank you so much!



QUOTE(spearfish @ 10 Mar, 2008 - 05:59 PM) *

QUOTE(dls76 @ 10 Mar, 2008 - 04:51 PM) *

CODE

echo
    "3. The statement '5 = $variable' will



That's your problem right there. Are you getting a parse error? Because it's likely that PHP is trying to:
CODE

echo $variable'


Your question was ambiguous as to what you are trying to do. If you want it to echo the variable, you need to separate it from the apostrophe like this:
CODE

echo "{$variable}'"


Remember variables in double quotes will expand, but not if PHP is looking for the wrong variable!

Another thing you might be trying to do is have it literally type "$variable", in which case you need to escape the dollar sign like this:
CODE

echo "\$variable"


Hope I helped, and feel free to correct me.
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spearfish
RE: How Do I Print A Variable Name?
10 Mar, 2008 - 05:24 PM
Post #4

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Glad I could help you out pirate.gif
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