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Need help in this program

Need help in this program

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arslan_09	19 May, 2008 - 01:17 PM Post #1
New D.I.C Head Joined: 14 Apr, 2008 Posts: 49 My Contributions	Write a C++ program which will display first 100 composite numbers. Composite integers are those integers which have more than two factors. In this program, you are not allowed to use for loop. CODE #include <iostream> using namespace std; void main() { int x,y; x=2; while(x<=100) { y=2; while(y<=x) if((x%1==0)&&(x%y==0)) { cout<<x; x++; y++; } cout<<"\n"; } } i don't understand where is the problem please help me.
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skyhawk133	RE: Need Help In This Program 19 May, 2008 - 01:20 PM Post #2
Head DIC Head Joined: 17 Mar, 2001 Posts: 14,920 Thanked: 47 times Dream Kudos: 1650 Expert In: Web Development My Contributions	What errors are you getting? What is the program doing that it shouldn't be doing? What isn't the program doing that it should be?
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arslan_09	RE: Need Help In This Program 19 May, 2008 - 05:53 PM Post #3
New D.I.C Head Joined: 14 Apr, 2008 Posts: 49 My Contributions	QUOTE(skyhawk133 @ 19 May, 2008 - 02:20 PM) What errors are you getting? What is the program doing that it shouldn't be doing? What isn't the program doing that it should be? the program does not show any error but the loop runs for infinite times.
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gabehabe

RE: Need Help In This Program
19 May, 2008 - 06:37 PM

Post #4

Donkey DIC

Joined: 6 Feb, 2008
Posts: 5,514

Windows

Thanked: 96 times
Dream Kudos: 2650
Expert In: ruling the world.

My Contributions

Hi arslan

Here's your code, commented:

cpp

#include <iostream>

using namespace std;

int main() // main should ALWAYS return an int
{
    int x,y; // int x and y
    x=2;
    while(x<=100) 
    {
        y=2; // set y to 2 at the beginning of each loop
        while(y<x) // if it is <= it will reach == where it is always divisible
        {
            if (x % y == 0) // if y can go into x with NO remainder
            {
                cout << x; // then print x
                break; // and break from the loop
            }
            y++; // continue inside your nested loop
        }
        x++; // continue your outer loop
        cout<< endl; // print a new line
    }
    
    cin.get ();
    return EXIT_SUCCESS;
}

I'm not sure if it's the result you're after, but it certainly isn't an infinite loop anymore

Hope this helps

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arslan_09

RE: Need Help In This Program
20 May, 2008 - 02:14 AM

Post #5

New D.I.C Head

Joined: 14 Apr, 2008
Posts: 49

Windows

My Contributions

QUOTE(gabehabe @ 19 May, 2008 - 07:37 PM)

Hi arslan

Here's your code, commented:

cpp

#include <iostream>

using namespace std;

int main() // main should ALWAYS return an int
{
    int x,y; // int x and y
    x=2;
    while(x<=100) 
    {
        y=2; // set y to 2 at the beginning of each loop
        while(y<x) // if it is <= it will reach == where it is always divisible
        {
            if (x % y == 0) // if y can go into x with NO remainder
            {
                cout << x; // then print x
                break; // and break from the loop
            }
            y++; // continue inside your nested loop
        }
        x++; // continue your outer loop
        cout<< endl; // print a new line
    }
    
    cin.get ();
    return EXIT_SUCCESS;
}