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Calculations using user input numbers

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Calculations using user input numbers

jlgraham	26 Jun, 2008 - 06:58 AM Post #1
New D.I.C Head Joined: 24 Jul, 2007 Posts: 5 My Contributions	Thanks for your help and I understand the reasoning but it still won't work. I have to store the result in an int variable and I get the error result already define in main double result = num3-num2; I don't understand how to get the results to an int unless I can explicitly make it but how. More help please.
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rgfirefly24	RE: Calculations Using User Input Numbers 26 Jun, 2008 - 08:07 AM Post #2
D.I.C Regular Joined: 7 Apr, 2008 Posts: 335 Thanked: 5 times Dream Kudos: 150 My Contributions	QUOTE(jlgraham @ 26 Jun, 2008 - 07:58 AM) Thanks for your help and I understand the reasoning but it still won't work. I have to store the result in an int variable and I get the error result already define in main double result = num3-num2; I don't understand how to get the results to an int unless I can explicitly make it but how. More help please. show us your code please and remember to use the code tages (the pound symbol on toolbar when you do a fulledit/new post)
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Locke37	RE: Calculations Using User Input Numbers 26 Jun, 2008 - 10:23 AM Post #3
Contributor of the Year Joined: 20 Mar, 2008 Posts: 1,270 Thanked: 56 times Dream Kudos: 325 My Contributions	Dream.In.Code has a policy by which we prefer to see a good faith effort on your part before providing source code for homework assignments. Please post the code you have written in an effort to resolve the problem, and our members would be happy to provide some guidance. Be sure to include a description of any errors you are encountering as well. Please post like this: Thank you for helping us helping you. __________________________________________________________ Alrighty then, now that that's covered... Theoretically, it sounds like you just need to change the name of the result variable. Are you doing this? java double result; double result = num3 - num2; Or are you doing this? java double result; result = num3 - num2; You only have to say double once. This post has been edited by Locke37: 26 Jun, 2008 - 10:25 AM
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