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Streams and Basic File I/O

 
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Streams and Basic File I/O, Creating ASCII data ( rows x columns) from an input file to ofstream (
ozz_blade
post 17 Jul, 2008 - 08:10 AM
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Task of Program: I want to create this program that runs an input file (test.txt) that contains a matrix with dimensions (11 x11) meaning that there are 11 rows x 11 columns in the file called "test.txt". I want to read the exact dimension into an outfile (ofstream). However, After program is run, the final output is a huge line with all the data combined in the first line (0 0 0 0 0 0 0 0 16 0 0 0 0 0 0 0 0 0 0 0 16 16 16 16 16 16 0 0 0 0 0 0 0....). I am supposed to get the same table that I have in the input file (11 rows x 11 columns), but not a line. I have the right program because it runs perfectly in the output screen, but not when I want to create an outfile ("outdata.txt")What can I Do??
CODE

// Headers
#include <iostream>
#include <algorithm>
#include <iterator>
#include <fstream>
#include <cstddef>
#include <cstdlib>

using namespace std;


// Define variables
typedef float value_type;

int main ()
{
    // Does the file exist?
    ifstream infile;
    infile.open("test.txt");
    ofstream outfile;
    outfile.open("outdata.txt");
    
    value_type data[11*11];
    
    copy(istream_iterator<value_type>(infile),istream_iterator<value_type>(),data);
    
    // Initialize Program
    int n=0,m=0;
    for (n=0; n < 11; n++)
    {
        for (m=0; m < 11; m++)
        {
            outfile << data[(n*11+m)]<< endl;
        }
        std::clog << std::endl;
    }
    infile.close();
    outfile.close();
    return 0;
}
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stayscrisp
post 18 Jul, 2008 - 07:10 PM
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dont know if im right but if you want to print out a 2 dimensional array then you should create a 2 dimensional array,

so instead of [11*11] you could use [11][11] pretty sure that should solve ur problem. because the thing is you still just passing in an int even if it is multiplied your still just making a one dimensional array of 121 ints, try this


good luck
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Einherjar
post 18 Jul, 2008 - 09:23 PM
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QUOTE(stayscrisp @ 18 Jul, 2008 - 10:10 PM) *

dont know if im right but if you want to print out a 2 dimensional array then you should create a 2 dimensional array,

so instead of [11*11] you could use [11][11] pretty sure that should solve ur problem. because the thing is you still just passing in an int even if it is multiplied your still just making a one dimensional array of 121 ints, try this


good luck


Well, you can split a 1 dimensional array into as many dimensions as you want in theory, it's just easier to look at it as [][].

And see if this works:

CODE

for (n=0; n < 11; n++)
    {
        for (m=0; m < 11; m++)
        {
            outfile << data[(n*11+m)];
        }
        std::clog << std::endl;
        outfile << endl; // or outfile << "\n";
    }
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baavgai
post 19 Jul, 2008 - 02:18 AM
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QUOTE(stayscrisp @ 18 Jul, 2008 - 10:10 PM) *

dont know if im right but if you want to print out a 2 dimensional array then you should create a 2 dimensional array,


Noooo! Um, sorry.

Two dimensional arrays are a bit of a mess, honestly. They're nice enough for a one off but for anything serious I'd take the time flatten the little error prone beasts out. Worst case in a C++ prog is you end up with some funky jagged array that never really gets disposed properly. Pointer pointers and lovely **argv type syntax in C.

Using a standard derived index form (row*cols + col) is simple enough and I'd never advise anyone against it who's already using it.

Anyway, that's not the issue. It looks like the the prior answer of capping it with a new line may be it.
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stayscrisp
post 19 Jul, 2008 - 10:06 AM
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problem solved smile.gif
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