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rohitkp	19 Jul, 2008 - 09:40 AM Post #1
New D.I.C Head Joined: 19 Jul, 2008 Posts: 2	when we accept an integer in any c++ compiler and we enter a "ZERO" before the other numeric value, the compiler takes only zero... for example if we enter 008 , in a integer , logically 8 should be taken by the compiler but it takes 0. so can any one solve this.? i would entertain only solutions which solve this problem keeping the data type as int or float and not converting it into a char....please beware,.
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NickDMax	19 Jul, 2008 - 09:51 AM Post #2
2B\|\|!2B Joined: 18 Feb, 2007 Posts: 2,756 Thanked 34 times Dream Kudos: 525 My Contributions	Well your question does not make a great deal of sense to me so let me see if I can sort this out: You seem to be talking about entering numbers into a "compiler" which seems to indicate that you are trying to write a bit of code like: int A = 0008; Now the problem with this is that C/C++ will view a number of the form 0ddd (where d is a digit) as an octal input. Now the second portion of your program seems to indicate that you are taking in an input in your program (which means you misspoke about the"compiler" portion above). So you are trying to use something like scanf or cin to input a value. But scanf and cin have no problem reading "00008" properly. So I guess I just don't understand your problem.
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