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Create dynamic page with PHP

 
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Create dynamic page with PHP
cygnusX
post 23 Jul, 2008 - 07:49 AM
Post #1


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Joined: 19 May, 2007
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Ok,i have some buttons,and drop-down boxes and when one of the buttons is clicked or the visitor choose item from the drop-down box the content in certain div must be replaced with data from a database.How to do that?I'm new to web programming so please give some good example...yes,there are many tutorials on internet but they're very vague and very different from each other and that's confusing.I need just a simple example(if it's possible).

This post has been edited by cygnusX: 23 Jul, 2008 - 07:51 AM
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grimpirate
post 23 Jul, 2008 - 12:03 PM
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PHP
echo '<form method="POST" action="' . basename(__FILE__) . '">';
echo '<p><input type="radio" name="yes" CHECKED> Yes</p>';
echo '<p><input type="radio" name="no"> No</p>';
echo '<input type="submit">';
echo '</form>';
if(isset($_POST['yes'])){
echo 'YES';
}else{
echo 'NO';
}
By selecting an alternate radio button you'll see the page switch from YES to NO as you submit the form.
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cygnusX
post 24 Jul, 2008 - 10:41 AM
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Well,i don't know what this code really does,but i doubt it will do what i want.I said "the content in certain div must be replaced with data from a database".Thanks anyway...some other guy said that i must use JavaScript/Ajax to do that.I thought that's very simple task.Isn't that the way most of the webpages works?I just need to connect to the database,and according to the incoming information from the database to create some elements in the page - divs,images,text,blah blah...
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coolbhatia18
post 24 Jul, 2008 - 11:33 PM
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Posts: 5
<code>
<?php
$conn = mysql_connect("localhost","varun","iceman");
mysql_select_db("gamesframework",$conn);

$sql = "SELECT * FROM category";
$display_block="<ul>";
$result = mysql_query($sql, $conn) or die(mysql_error());

while ($newArray = mysql_fetch_array($result))
{
$name= $newArray['name'];
$id= $newArray['id'];
$display_block .= "
<li><a href=\"viewgameslist.php?id=$id\">
<strong>$name</strong></a><br>

";
}
$display_block .="</ul>";



if ($_GET[id]>0)
{
$sql1 = "SELECT * FROM category_game where category_id = $_GET[id]";
$display_block1="<ul>";
$result1 = mysql_query($sql1, $conn) or die(mysql_error());

while ($newArray1 = mysql_fetch_array($result1))
{
$game_id1= $newArray1['game_id'];

$sql2 = "SELECT name,id FROM game where id = '$game_id1'";
$result2 = mysql_query($sql2, $conn) or die(mysql_error());
while ($newArray2 = mysql_fetch_array($result2))
{
$game_name= $newArray2['name'];
$id=$newArray2['id'];




$display_block1 .= "
<li><a href=\"viewgamedetails.php?id=$id\">
<strong>$game_name</strong></a><br>

";
}
}
$display_block1 .="</ul>";
}
?>

<html>
<head>
<title>Update Game</title>
</head>
<body>
<spacer type=horizontal size=300>
<a href="index.php">
<strong>Home</strong></a><br>
<h1>Choose Game Category</h1>
<p><?php echo $display_block ?></p>
<p><?php echo $display_block1 ?></p>



</body>
</html>
</code>

hope this helps.... i reload the same page and pass value 2 it usin GET. when there is a user click its corresponding value is passed.. and $display_block1 is generated an displayed... if u dnt understand completely ... do ask!
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