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Terminating string with multiple characters.

Terminating string with multiple characters.

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zerogee	20 Aug, 2008 - 03:06 PM Post #1
New D.I.C Head Joined: 20 Aug, 2008 Posts: 45	Hi, I need help. I need to ternimate a string with a '.' or '?' or '!' and then count the number of (user input) character that occur in the string. Problem is my code works if i end the string with \n. but when i code it to terminate the string with '.' or '?' or '!' it will not let me input a character and gives me a number of occurances that are not right. CODE #include <iostream> #include <string> #include <algorithm> using namespace std; int main () { int userInput, num_comma; string message; { cout << "Enter string that is terminating with a '.': \n"; getline(cin, message, '.'); cout << "\nString entered is: \n" << message; cout << "\n\nEnter a single character followed by the Enter key: "; userInput = cin.get(); } int num_commas = count(message.begin(), message.end(), userInput); //num_commas holds the number of elements in text cout << "\n\n" << "The letter occurs " << num_commas << " times in the string.\n\n"; return 0; } This post has been edited by zerogee: 20 Aug, 2008 - 04:04 PM
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gabehabe

20 Aug, 2008 - 03:10 PM

Post #2

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Joined: 6 Feb, 2008
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Do you just mean this:

cpp

#include <iostream>
#include <string>
#include <algorithm>

using namespace std;
int main ()
{
int userInput, num_comma;


string message;
  {
      cout <<  "Curtis Gassen Week 2 Project, #2\n";
      cout << "======================================\n\n";

   cout << "Enter string that is terminating with a '.': \n";
   getline(cin, message, '.');

   cout << "\nString entered is: \n" << message;

   cout << "\n\nEnter a single character followed by the Enter key: ";
   userInput = cin.get();


  }

int num_commas = count(message.begin(), message.end(), userInput);  //num_commas holds the number of elements in text

cout << "\n\n" << "The letter occurs " << num_commas << " times in the string.\n\n";

return 0;
}

?
More specifically: getline(cin, message, '.');

Oh, and cin.get() will accept enter without a character before it

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zerogee

20 Aug, 2008 - 03:20 PM

Post #3

New D.I.C Head

Joined: 20 Aug, 2008
Posts: 45

QUOTE(gabehabe @ 20 Aug, 2008 - 04:10 PM)

Do you just mean this:

cpp

#include <iostream>
#include <string>
#include <algorithm>

using namespace std;
int main ()
{
int userInput, num_comma;


string message;
  {
      cout <<  "Curtis Gassen Week 2 Project, #2\n";
      cout << "======================================\n\n";

   cout << "Enter string that is terminating with a '.': \n";
   getline(cin, message, '.');

   cout << "\nString entered is: \n" << message;

   cout << "\n\nEnter a single character followed by the Enter key: ";
   userInput = cin.get();


  }

int num_commas = count(message.begin(), message.end(), userInput);  //num_commas holds the number of elements in text

cout << "\n\n" << "The letter occurs " << num_commas << " times in the string.\n\n";

return 0;
}

?
More specifically: getline(cin, message, '.');

Oh, and cin.get() will accept enter without a character before it

sorry, i modify the code right after i posted. I already know this code;

CODE

getline(cin, message, '.');

but when the code is entered this way it will not allow a user input for a character to search.

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gabehabe	20 Aug, 2008 - 03:24 PM Post #4
Working Girl. Joined: 6 Feb, 2008 Posts: 5,440 Thanked 94 times Dream Kudos: 2625 Expert In: ruling the world. My Contributions	Ahh, the second buffer question of the night. It stores crap in a temporary buffer after the getline, so you need to make a call to cin.ignore(); right after getline, like so: cpp getline(cin, message, '.'); cin.ignore(); Hope this helps
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zerogee	20 Aug, 2008 - 03:30 PM Post #5
New D.I.C Head Joined: 20 Aug, 2008 Posts: 45	QUOTE(gabehabe @ 20 Aug, 2008 - 04:24 PM) Ahh, the second buffer question of the night. It stores crap in a temporary buffer after the getline, so you need to make a call to cin.ignore(); right after getline, like so: cpp getline(cin, message, '.'); cin.ignore(); Hope this helps I tried the CODE getline(cin, message, '.'); cin.ignore(); but it still will not allow me to enter a character to search. The program complies with no errors and 2 warnings that point to this line; CODE int num_commas = count(message.begin(), message.end(), userInput); //num_commas holds the number of elements in text but i do not think this is the problem
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gabehabe	21 Aug, 2008 - 03:13 AM Post #6
Working Girl. Joined: 6 Feb, 2008 Posts: 5,440 Thanked 94 times Dream Kudos: 2625 Expert In: ruling the world. My Contributions	You declare userInput as an int. Try declaring it as a char.
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zerogee	21 Aug, 2008 - 03:23 AM Post #7
New D.I.C Head Joined: 20 Aug, 2008 Posts: 45	QUOTE(gabehabe @ 21 Aug, 2008 - 04:13 AM) You declare userInput as an int. Try declaring it as a char. That worked, Thanks!!
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