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Fibonacci Numbers

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Fibonacci Numbers

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duskmon10	7 Oct, 2008 - 04:43 PM Post #1
D.I.C Head Joined: 1 Oct, 2008 Posts: 94	The program is similar to the fibonnaci numbers. Here's the entire problem: One place the fibonnaci numbers occur is as certain population growth rates. If a population has no deaths, then the series shows the size of the population after each time period. The formula applies most straightforwardly to asexual reproduction at a rate of one offspring per time period. Assume that the green crud population grows at this rate and has a time period of 5 days. Hence, if a green crud population starts out as 10 pounds of crud, then in 5 days there is still 10 pounds of curd; in 10 days there is 20 pounds of crud, in 15 days 30 pounds in 20 days 50 pounds, and so forth. Write a program that takes both the initial size of a green crud population (in pounds) and a number of days as input, and that outputs the number of pounds of green crud after that many days. Assume that the population size is the same for four days and then increases every fifth day. Your program should allow the user to repeat this calculation as often as desired. Here's what I have so far: CODE #include <iostream> using namespace std; double population(int pop, int time); int main() { int final, pop, time; cout<<"Plese enter in the initial size of the green crud."<<endl; cin>>pop; cout<<"Please enter in the time in days."<<endl; cin>>time; final = population(int pop, time) cout<<"The number of crud is "<<final<<endl; return 0; } double population(int pop, int time) { if(time%5==0) { pop = time + pop; if(time<=5) pop = 5; } else(pop = pop); return pop; } And I got the following errors: 1>c:\users\owner\documents\visual studio 2008\projects\homework5-1\homework5-1\question1.cpp(11) : error C2144: syntax error : 'int' should be preceded by ')' 1>c:\users\owner\documents\visual studio 2008\projects\homework5-1\homework5-1\question1.cpp(11) : error C2660: 'population' : function does not take 0 arguments 1>c:\users\owner\documents\visual studio 2008\projects\homework5-1\homework5-1\question1.cpp(11) : error C2059: syntax error : ')' Thanks in advance for your help.
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GWatt	7 Oct, 2008 - 04:54 PM Post #2
human inside Joined: 1 Dec, 2005 Posts: 2,149 Thanked 16 times Dream Kudos: 450 My Contributions	final = population(int pop, time) You don't need that 'int' in there when you call population. just do poulation(pop, time) This post has been edited by GWatt: 7 Oct, 2008 - 04:55 PM
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BetaWar	7 Oct, 2008 - 04:56 PM Post #3
#include <soul.h> Joined: 7 Sep, 2006 Posts: 1,981 Thanked 77 times Dream Kudos: 1175 My Contributions	I have debugged it, but I don't think it works as it should, the population function seems to be off in its results.: CODE #include <iostream> using namespace std; int population(int pop, int time); int main(){ int pop; int time; int final; cout<<"Plese enter in the initial size of the green crud."<<endl; cin>>pop; cout<<"Please enter in the time in days."<<endl; cin>>time; final = population((int)pop, (int)time); cout<<"The number of crud is "<<final<<endl; return 0; } int population(int pop, int time){ if(time%5==0){ pop += time; if(time<=5) pop = 5; } return pop; }
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duskmon10	7 Oct, 2008 - 05:05 PM Post #4
D.I.C Head Joined: 1 Oct, 2008 Posts: 94	I fixed all of the errors, here's the new code: CODE #include <iostream> using namespace std; int population(int pop, int time); int main() { int final, pop, time; cout<<"Plese enter in the initial size of the green crud."<<endl; cin>>pop; cout<<"Please enter in the time in days."<<endl; cin>>time; final = population(pop, time); cout<<"The number of crud is "<<final<<endl; return 0; } int population(int pop, int time) { if(time%5==0) { pop = time + pop; if(time<=5) pop = 5; } else(pop = pop); return pop; } Now I just need to add in the code to let the user repeat the program. How do I do that? I want to ask them if they want to continue and ask them to either enter in Y or N for an answer.
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GWatt	7 Oct, 2008 - 05:15 PM Post #5
human inside Joined: 1 Dec, 2005 Posts: 2,149 Thanked 16 times Dream Kudos: 450 My Contributions	Put the code for getting user input, and printing out the result inside of a do while loop CODE char repeat; do { //stuff } while (repeat = 'y' \|\| repeat = 'Y')
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duskmon10	7 Oct, 2008 - 05:16 PM Post #6
D.I.C Head Joined: 1 Oct, 2008 Posts: 94	Where do I put that inside of the program?
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GWatt	7 Oct, 2008 - 05:22 PM Post #7
human inside Joined: 1 Dec, 2005 Posts: 2,149 Thanked 16 times Dream Kudos: 450 My Contributions	wherever you have the code that interacts with the user. you have yours inside of the main function you should also ask them if they want to repeat, and get input for that.
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BetaWar	7 Oct, 2008 - 05:24 PM Post #8
#include <soul.h> Joined: 7 Sep, 2006 Posts: 1,981 Thanked 77 times Dream Kudos: 1175 My Contributions	Youu would put it in your main loop. However the code given above doesn't work out of the box, it needs some assembly (like getting it to compile correctly) CODE #include <iostream> using namespace std; int population(int pop, int time); int main(){ char repeater; do{ repeater = 'n'; int pop = 0; int time = 0; int final = 0; cout<<"Plese enter in the initial size of the green crud."<<endl; cin>>pop; cout<<"Please enter in the time in days."<<endl; cin>>time; final = population((int)pop, (int)time); cout<<"The number of crud is "<<final<<endl; cout<<"Would you like to repeat the program?"<<endl; cin>>(char)repeater; } while(repeater == 'y' \|\| repeater == 'Y'); return 0; } int population(int pop, int time){ if(time%5==0){ pop += time; if(time<=5) pop = 5; } return pop; } Hope that helps.
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duskmon10	7 Oct, 2008 - 05:27 PM Post #9
D.I.C Head Joined: 1 Oct, 2008 Posts: 94	It doesn't work, it asks me if I want to repeat twice and then the program ends. Here's the code: CODE #include <iostream> using namespace std; int population(int pop, int time); int main() { int final, pop, time; cout<<"Plese enter in the initial size of the green crud."<<endl; cin>>pop; cout<<"Please enter in the time in days."<<endl; cin>>time; final = population(pop, time); cout<<"The number of crud is "<<final<<endl; char ans; do { cout<<"Would you like to repeat the program? Y or N."<<endl; cin>>ans; } while ((ans == 'y'\|\|ans == 'Y')); return 0; } int population(int pop, int time) { if(time%5==0) { pop = time + pop; if(time<=5) pop = 5; } else(pop = pop); return pop; }
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GWatt

7 Oct, 2008 - 05:30 PM

Post #10

human inside

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you have to pu the do { before you get user input about the program

cpp


    do
    {
        cout<<"Plese enter in the initial size of the green crud."<<endl;
        cin>>pop;
        cout<<"Please enter in the time in days."<<endl;
        cin>>time;
        final = population(pop, time);
        cout<<"The number of crud is "<<final<<endl;
        char ans;
    
        cout<<"Would you like to repeat the program? Y or N."<<endl;
        cin>>ans;
    }
    while ((ans == 'y'||ans == 'Y'));
    return 0;

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BetaWar	7 Oct, 2008 - 05:30 PM Post #11
#include <soul.h> Joined: 7 Sep, 2006 Posts: 1,981 Thanked 77 times Dream Kudos: 1175 My Contributions	All you are repeating with this code is asking if the user wants to repeat it. CODE char ans; do { cout<<"Would you like to repeat the program? Y or N."<<endl; cin>>ans; } while ((ans == 'y'\|\|ans == 'Y')); Not only that, but it also will run ahead and not allow you to input more data unless you change the value of ans each time through the loop. Look at the code I posted in my last post. Hope that helps.
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duskmon10	7 Oct, 2008 - 05:33 PM Post #12
D.I.C Head Joined: 1 Oct, 2008 Posts: 94	Now I got an error saying that ans was undeclared: CODE #include <iostream> using namespace std; int population(int pop, int time); int main() { do { int final, pop, time; cout<<"Plese enter in the initial size of the green crud."<<endl; cin>>pop; cout<<"Please enter in the time in days."<<endl; cin>>time; final = population(pop, time); cout<<"The number of crud is "<<final<<endl; char ans; cout<<"Would you like to repeat the program? Y or N."<<endl; cin>>ans; } while ((ans == 'y'\|\|ans == 'Y')); return 0; } int population(int pop, int time) { if(time%5==0) { pop = time + pop; if(time<=5) pop = 5; } else(pop = pop); return pop; }
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