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Roman numerals (olde style)

 

Roman numerals (olde style)
Inkman

14 Oct, 2008 - 12:15 PM
Post #1

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Joined: 6 Oct, 2008
Posts: 11


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Ok, I got to where it will take the numbers, if I put is the exact numbers I get the letters.

I just don't know what I need to make it add all the numbers up.

So if I want to put 4 I get "IIII" or 3102 I get "MXII".

Here is what I've got.

CODE
roman = gets.chomp.to_i

if roman == 1
  puts 'I'
    elsif roman == 5
      puts 'V'
        elsif roman == 10
          puts 'X'  
            elsif roman == 50
              puts 'L'  
                elsif roman == 100
                  puts 'C'            
                    elsif roman == 500
                      puts 'D'
                        elsif roman == 1000
                          puts 'M'
                            

puts roman.to_i
end
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RandCode

RE: Roman Numerals (olde Style)

23 Oct, 2008 - 08:19 AM
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Joined: 23 Oct, 2008
Posts: 7


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In my opinion, that script, as is, will never say a good translation between numbers and romans ones.
In the way you wrote it, the program, does what you write, it sees a 4 and it uses the I cause you didn't made it understand the exceptions, like IV, cause, it says: if you see a 5, write V, but, even the 4 needs the V.

I'm starting with Ruby so I can't give you a code answer yet, but this is my hint:
Split the number starting from the big to small like:

3102 is divisible for 1000? get the integer of that and go on taking off the 3 from the number
102 is divisible for 500? no, so go for the 100. How many? 1 and take it off.
2 is divisible for 5 go for the 1.

In this way is a more checked way to do it. not perfect, but better.

Another hint to make it accettable, make it check the numbers 4, and 9 to make it IV IX and test it again.
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