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even and odd numbers

 

even and odd numbers, help with even and odd numbers
philip soraghan

9 Nov, 2008 - 04:17 PM
Post #1

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Joined: 3 Apr, 2008
Posts: 9
hi there i need help finding the sum of a set of even and odd integers in a set of integers like 4567 odds would be 12 evens would be 10 all i get is if i enter 4567 i get 4567 and 0
CODE

#include <cstdlib>
#include <iostream>

using namespace std;

int main(int argc, char *argv[])
{
    int limit;
    int number;
    
    int sumeven=0;
    int sumodd=0;
    int count =0;
    cout<<"Enter limit of numbers "<<endl;
    cin>>limit;
    cout<<"Enter number"<<endl;
    cin>>number;


  
    if (number % 2 ==0)
{
    sumeven = count + number;
    count++;

  

}

cout<<"The sum of the even numbers are "<<sumeven<<endl;
    cout<<"The sum of the odd  numbers are "<<sumodd<<endl;
          

  
    system("PAUSE");
    return EXIT_SUCCESS;
}
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GWatt

RE: Even And Odd Numbers

9 Nov, 2008 - 04:31 PM
Post #2

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My Contributions
You need to break up the number into digits.
The easiest way to do this is read the characters into a string and then take the sum of the values of the digits
cpp

string num;
int even = 0, odd = 0;
cin >> num;
for (int i = 0; i < num.length(); i++)
{
    if (num[i] - '0' % 2 == 0) //need to subtract '0' because we're dealing with ascii characters
        even += num[i] - '0';
    else
        odd += num[i] - '0';
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