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logic problem

 
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logic problem, no duplicates in input
progstud
8 Jan, 2009 - 02:12 AM
Post #1

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Hi guys..back again...I was confused if i should start another topic...anyways.. I am working a problem at the moment that ask the user to enter 10 integers greater than 10. Also the number should be printed only if it is not a duplicate(already entered). Really my problem is more about logic at the moment..
CODE
#include<stdio.h>

int main(void)
{
    int array[5];
    int i;
    int number;
    int j;
    
    for(i=0;i<5;i++)
    {
        do
        {
        printf("Enter a number..not duplicate and greater than 10: ");
        scanf("%d",&number);
        
        }while(number<=10 );
        
        array[i]=number;
        
    }
    
    /* printing array */
    for(i=0;i<5;i++)
    {
        printf("a[%d] %d",i,array[i]);
        printf("\n");
    }
}
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Stofke
RE: Logic Problem
8 Jan, 2009 - 04:40 AM
Post #2

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Should it be something like that?

CODE

#include <stdio.h>
#include <stdlib.h>

int main()
{
     int array[5];
     int i,j,number;
    for (i=0;i<5;i++)
    {
REDO:
        printf("Enter a number..not duplicate and greater than 10: ");
        scanf("%d",&number);
        if (number <10){
        array[i]=number;
        }

        for ( j = 0; j < i; ++j )
        {
            if ( array[i] == array[j] )
            {
                printf("already in the array ! try again \n");
                goto REDO;
            }
        }
    }

    /* printing array */
    for(i=0;i<5;i++)
    {
        printf("a[%d] %d",i,array[i]);
        printf("\n");
    }
}
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Gloin
RE: Logic Problem
8 Jan, 2009 - 05:18 AM
Post #3

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Unless you wanna switch to using some more suitable datastructure than arrays, what you need to do is.

* Loop
* Ask for a number
* See if it's already in the array
* If it isn't, put it into the array and update the array size
* Stop when the array size equals 10

The only reason I'm making this post is because I see absolutely no reason to use GOTO statements here.
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