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Tic Tac Toe

Tic Tac Toe, winner, looser, or tie: problems concerning 2D array

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cbc123	10 Jan, 2009 - 12:42 PM Post #1
New D.I.C Head Joined: 10 Jan, 2009 Posts: 30 My Contributions	I having trouble with finding out the winner, looser or tie. I did some if statments,but none worked. I'd appreciate any tips, thanks, kyle. CODE #include <iostream> #include <iomanip> using namespace std; const int ROW = 3; const int COL = 3; void showGrid(char grid[][COL], int); int main() { char grid[ROW][COL] = {{'', '', ''}, {'', '', ''}, {'', '', ''}}; int rows, cols; int el = 1; cout << " TIC TAC TOE" << endl; do { showGrid(grid, ROW); cout << "\nPlayer X, Enter the row and column:"; cin >> rows >> cols; if (grid[rows-1][cols-1] != '') {cout << "\nThis space is taken... Enter the row and column:\n"; cin >> rows >> cols; } else grid[rows-1][cols-1] = 'X'; showGrid(grid, ROW); cout << "\nPlayer O, Enter the row and column:"; cin >> rows >> cols; if (grid[rows-1][cols-1] != '') {cout << "This space is taken... Enter the row and column:\n"; cin >> rows >> cols; } else grid[rows-1][cols-1] = 'O'; /if(grid[0][0] =='X'&& grid[0][1]=='X' && grid[0][2]=='X') { cout << "Player X wins this game."; }*/ } while(el = 1); showGrid(grid, ROW); return 0; } void showGrid(char array[][COL], int numRows) { for (int row = 0; row < numRows; row++) { for (int col = 0; col < COL; col++) { cout << setw(2) << array[row][col] << " "; } cout << endl; } }
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Psionics

RE: Tic Tac Toe
10 Jan, 2009 - 01:22 PM

Post #2

D.I.C Head

Joined: 6 Sep, 2008
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Well there's a couple ways to check the winner, but typically you'll want to check horizontal wins, vertical wins, and then the two cross wins:

cpp


	// check horizontal
	for (int i = 0; i < 3; ++i)
	{
		if (theBoard[i][i] != EMPTY)
			if (theBoard[i][0] == theBoard[i][1] && theBoard[i][1] == theBoard[i][2])
				return true;
	}

	// check vertical
	for (int i = 0; i < 3; ++i)
	{
		if (theBoard[i][i] != EMPTY)
			if (theBoard[0][i] == theBoard[1][i] && theBoard[1][i] == theBoard[2][i])
				return true;
	}

	// check right cross
	if (theBoard[0][0] != EMPTY)
	{
		if (theBoard[0][0] == theBoard[1][1] && theBoard[1][1] == theBoard[2][2])
			return true;
	}

	// check left cross
	if (theBoard[0][2] != EMPTY)
	{
		if (theBoard[0][2] == theBoard[1][1] && theBoard[1][1] == theBoard[2][0])
			return true;
	}

Obviously EMPTY would be a #define somewhere, or whatever you have in your array

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Bench	RE: Tic Tac Toe 10 Jan, 2009 - 01:30 PM Post #3
D.I.C Addict Joined: 20 Aug, 2007 Posts: 827 Thanked: 57 times Dream Kudos: 150 Expert In: C/C++ My Contributions	Instead of repeating a message I posted a while ago, here's a link to a thread on the same topic http://www.dreamincode.net/forums/index.ph...=15&t=41074
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Martyr2	RE: Tic Tac Toe 10 Jan, 2009 - 01:32 PM Post #4
Programming Theoretician Joined: 18 Apr, 2007 Posts: 6,656 Thanked: 613 times Expert In: C/C++, Java, VB, VB.NET, C#, PHP, Web Development, HTML & CSS, Javascript My Contributions	well the best way to think of this is that you are going to need some loops. A loop which checks a row inside a loop which loops through each row. Same with columns. Then you just need to check diagonals. Each of these winning checks should be in its own function. Make three functions called "checkRows()" which will be used to check each row for three of a kind. Another called "checkColumns()" which will then check each column. Last "checkDiagonals()" to check the diagonals. Here is how you might check your rows... cpp // Returns true if a win, false if not. playerChar is either 'X' or 'O' bool checkRows(char grid[][3], char playerChar) { // Loop through each row for (int i = 0; i < 3; i++) { // Count will keep track player chars in row int count = 0; // Loop through each column checking if char // If it is, increment count for (int j = 0; j < 3; j++) { if (grid[i][j] == playerChar) { count++; } } // If we have 3, it means they have the row so they win. if (count == 3) { return true; } } // Nope, no win for rows return false; } So that will give you the general idea of how you can check for horizontal row wins for a player. You would pass it the grid after each player's turn and that player's char and it will check rows. So for checking for a win you will call all three checks: horizontal, vertical and diagonals. This should get you started. Enjoy! "At DIC we be tic tac toe winning code ninjas... in our version of war games, joshua always wins because we coded it!"
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cbc123	RE: Tic Tac Toe 10 Jan, 2009 - 03:51 PM Post #5
New D.I.C Head Joined: 10 Jan, 2009 Posts: 30 My Contributions	I've been at this project since early this morning and am starting to get eye bags, so please bear with me. I'm having trouble calling the the checkrows function it's self and am confused about where to call it. I don't have a lot of experience with bool types, so I've been gusing and checking. Heres what I got. CODE bool checkRows(char grid[][3], char);// checkrows protoype //call checkrows to test for winner if( checkRows(grid, ROW)) cout <<"x is winner"; else cout <<"o is winner"; bool checkRows(char grid[][3], char playerChar)
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Hyper	RE: Tic Tac Toe 10 Jan, 2009 - 04:01 PM Post #6
Banned Joined: 15 Oct, 2008 Posts: 2,129 Thanked: 87 times Dream Kudos: 425 My Contributions	Boolean data-type returns one of two things: true and false To call a function (regardless of being type int, void, char, bool, etc), you call it by name, EG: checkRows(); You can also pass it parameters, eg: checkRows(grid[][3], playerChar); This post has been edited by Hyper: 10 Jan, 2009 - 04:02 PM
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