[TomVdV]

Hi all,

a studid question.

I've include a pdf-file into my project.

It works when I'm working with the full path

"C:\\C-Sharp\\Voetbaladministratie\\Opstelling.pdf"

But I get an error on runtime when I'm trying to use a relative path.

I've tried the following thing:

"Opstelling.pdf"

"/Opstelling.pdf"

".../Opstelling.pdf"

but they didn't works.
Can somebody help me?

This post has been edited by TomVdV: 01 June 2009 - 03:42 AM

[fixo]

TomVdV, on 1 Jun, 2009 - 01:13 AM, said:

Hi all,

a studid question.

I've include a pdf-file into my project.

It works when I'm working with the full path
<code>"C:\\C-Sharp\\Voetbaladministratie\\Opstelling.pdf"</code>

But I get an error on runtime when I'm trying to use a relative path.

I've tried the following thing:
<code>"Opstelling.pdf"</code>
<code>"/Opstelling.pdf"</code>
<code>".../Opstelling.pdf"</code>

but they didn't works.
Can somebody help me?

Try to search for file by this path:

string fn = System.Windows.Forms.Application.StartupPath + "\\Opstelling.pdf";

~'J'~

[TomVdV]

string fn = System.Windows.Forms.Application.StartupPath + "\\Opstelling.pdf";
Messagebox.Show(fn);
//Process.Start("AcroRd32.exe","C:\\C-Sharp\\Voetbaladministratie\\Opstelling.pdf";
Process.Start("AcroRd32.exe, "fn");

The Messagebox shows me C:\C-Sharp\Voetbaladministratie\bin\Debug\Opstelling.pdf

Acrobat start up and give then an error: "There was an error opening this document. This file cannot be found"

[noorahmad]

for path use

String _Path = @"C:\directory\blabla\file.etc";

[TomVdV]

I have tried to add a @ before "fn", but without succes

string fn = System.Windows.Forms.Application.StartupPath + "\\Opstelling.pdf";
Messagebox.Show(fn);
//Process.Start("AcroRd32.exe","C:\\C-Sharp\\Voetbaladministratie\\Opstelling.pdf";
Process.Start("AcroRd32.exe, @"fn");

[noorahmad]

try this it is working on my computer

String _Path = @"C:\mypdf.pdf";
			System.Diagnostics.Process.Start("Acrobat.exe", _Path);

Note: Name of Process or Application Depend on it's Version.

This post has been edited by noorahmad: 01 June 2009 - 04:32 AM

[TomVdV]

it the same as

Process.Start("AcroRd32.exe","C:\\C-Sharp\\Voetbaladministratie\\Opstelling.pdf";

That also works for me.

But I want to use a relative path, so I can move the application to other directories and other PC's without changing al paths.

[noorahmad]

for opening a file use OpenFileDialog and assign it to Proocess.

[fixo]

TomVdV, on 1 Jun, 2009 - 03:37 AM, said:

it the same as

Process.Start("AcroRd32.exe","C:\\C-Sharp\\Voetbaladministratie\\Opstelling.pdf";

That also works for me.

But I want to use a relative path, so I can move the application to other directories and other PC's without changing al paths.

Sorry I don't see where is your file was stored
Usually I use something like this

Add
using System.IO to reference scope

Then let you try:

   string execPath = Path.GetDirectoryName(Assembly.GetExecutingAssembly().CodeBase);
				string strFileName = Path.Combine(execPath, "Opstelling.pdf");

~'J'~

[TomVdV]

noorahmad, on 1 Jun, 2009 - 11:40 AM, said:

for opening a file use OpenFileDialog and assign it to Proocess.

I've tried this

			OpenFileDialog openFileDialog1 = new OpenFileDialog();
			openFileDialog1.InitialDirectory = "c:\\";
			openFileDialog1.Filter = "pdf files (*.pdf)|*.pdf|All files (*.*)|*.*";
			openFileDialog1.FilterIndex = 2;
			openFileDialog1.RestoreDirectory = true;

			MessageBox.Show(openFileDialog1.FileName);

But when I run the application I didn't get an dialogbox, I only receive an empty messagebox

[SixOfEleven]

TomVdV, on 1 Jun, 2009 - 08:41 AM, said:

noorahmad, on 1 Jun, 2009 - 11:40 AM, said:

for opening a file use OpenFileDialog and assign it to Proocess.

I've tried this

			OpenFileDialog openFileDialog1 = new OpenFileDialog();
			openFileDialog1.InitialDirectory = "c:\\";
			openFileDialog1.Filter = "pdf files (*.pdf)|*.pdf|All files (*.*)|*.*";
			openFileDialog1.FilterIndex = 2;
			openFileDialog1.RestoreDirectory = true;

			MessageBox.Show(openFileDialog1.FileName);

But when I run the application I didn't get an dialogbox, I only receive an empty messagebox

You didn't show the dialog box.

openFileDialog1.ShowDialog();

[TomVdV]

fixo, on 1 Jun, 2009 - 01:14 PM, said:

Add
using System.IO to reference scope

Then let you try:

   string execPath = Path.GetDirectoryName(Assembly.GetExecutingAssembly().CodeBase);
				string strFileName = Path.Combine(execPath, "Opstelling.pdf");

I get a error on Assembly

[TomVdV]

SixOfEleven, on 1 Jun, 2009 - 02:57 PM, said:

You didn't show the dialog box.

openFileDialog1.ShowDialog();

			OpenFileDialog openFileDialog1 = new OpenFileDialog();
			openFileDialog1.InitialDirectory = "c:\\";
			openFileDialog1.Filter = "pdf files (*.pdf)|*.pdf|All files (*.*)|*.*";
			openFileDialog1.FilterIndex = 2;
			openFileDialog1.RestoreDirectory = true;
			openFileDialog1.ShowDialog();

			MessageBox.Show(openFileDialog1.FileName);

			Process.Start("AcroRd32.exe", @"openFileDialog1");

I've an error te load the file in acrobat that the file can't be found

[SixOfEleven]

TomVdV, on 1 Jun, 2009 - 09:18 AM, said:

SixOfEleven, on 1 Jun, 2009 - 02:57 PM, said:

You didn't show the dialog box.

openFileDialog1.ShowDialog();

			OpenFileDialog openFileDialog1 = new OpenFileDialog();
			openFileDialog1.InitialDirectory = "c:\\";
			openFileDialog1.Filter = "pdf files (*.pdf)|*.pdf|All files (*.*)|*.*";
			openFileDialog1.FilterIndex = 2;
			openFileDialog1.RestoreDirectory = true;
			openFileDialog1.ShowDialog();

			MessageBox.Show(openFileDialog1.FileName);

			Process.Start("AcroRd32.exe", @"openFileDialog1");

I've an error te load the file in acrobat that the file can't be found

You need to change this line:

Process.Start("AcroRd32.exe", @"openFileDialog1");

What you are passing Process.Start is: openFileDialog1 not the filename. When you put the quotes around it you are making what inside the quotes a string. You want to pass the variable, not the string.

You would want to do this to call the appropriate variable, like you did in the Message Box.

Process.Start("AcroRd32.exe", openFileDialog1.FileName);

Give that a try, hopefully it will help.

[noorahmad]

on btnClick Event use this code:

OpenFileDialog obj = new OpenFileDialog();
			if (obj.ShowDialog() == DialogResult.OK)
			{
				String _Path = obj.FileName;
				System.Diagnostics.Process.Start("Acrobat.exe", @_Path);
			}