[larry_lalonde]

So I wrote a program that accepts command line arguments and then reverses them. Nothing special.
I have this bit of code, which I created to store the length of each argument in a dynamically created array:

int *inputStrLen;
inputStrLen = malloc(argc * sizeof(int));

I am just wondering if I am misunderstanding how this works. Does it actually create a new array?

The program works perfectly as far as I can tell. And I ran tests with code like this to display the length of each argument, and it works fine.

// this is what would be entered in command prompt
c:\blahblah\programs\> stringrev brian no

// this is the code to test them
printf("Length: %d ", inputStrLen[1]);
printf("Length: %d ", inputStrLen[2]);

// this is the ouput
Length: 5 Length: 2

Sorry if this is a dumb question, but I'm only familiar really with the "new" operator in C++ with which one may unambiguously create a new array.

[Smurphy]

It does not actually create an array what it does is returns a pointer to the added memory. Here check this out it's pretty informative.
http://en.wikipedia.org/wiki/Malloc

[JackOfAllTrades]

It sets aside enough room in memory to hold argc contiguous integers and returns a pointer to the first element, which you can then access as if it was an array. Close enough for government work

[Notorion]

C or C++?

malloc I think is from C, correct me if I am mistaken.

If your looking on how to create and manage dynamic data in C++ I can help, but if you are looking for C help hopefully someone else knows.