[Emon_MQ]

hi i want to go through each of the charecter of a string without using str[loop counter].
like
for(int i=o;i<=str.length;i++)
str[i];

insted
for(int i=0;i<=str.length;i++)
str=str[1]+str[2]+str[3]....str[str.length();

any suggestion??

[redhotfire0]

Emon_MQ, on 11 Aug, 2009 - 09:41 AM, said:

hi i want to go through each of the charecter of a string without using str[loop counter].
like
for(int i=o;i<=str.length;i++)
str[i];

insted
for(int i=0;i<=str.length;i++)
str=str[1]+str[2]+str[3]....str[str.length();

any suggestion??

str[i] = str[1]+str[2]+str[3]

Do you mean the elements of string, or multiple different strings?

[Emon_MQ]

No actually its the combination of all the charecters of string.Actually I want to write a function which returns the reverse of an input string.

string reverseOfgiven(string str)
{
for(int i=string.length();i<=string.length();i--)
str=str[1]+str[2] //.up2 str[str.length()]

return str;
}

[bimbolena]

Emon_MQ, on 11 Aug, 2009 - 10:36 AM, said:

No actually its the combination of all the charecters of string.Actually I want to write a function which returns the reverse of an input string.

string reverseOfgiven(string str)
{
for(int i=string.length();i<=string.length();i--)
str=str[1]+str[2] //.up2 str[str.length()]

return str;
}

Try something like this:

string reverseOfgiven(string str)
 {
	string str2=str; // Or just create an empty string of the same length as str
	for(int i=0; i<string.length(); i++) {
		 str2[i]=str[string.length()-1-i];
	}
	return str2;
 }

[Emon_MQ]

Thanks it works!!!