[aries0152]

I like to solve a eqn using pointer to function. But I am having some problem in using it.

My code is-

 #include<iostream>
#include<cmath>

using namespace std;

double func(double t,double f)
{
	return 1.0/sqrt(1.0-pow((sin(t/2.0)*sin(f)),2));
}

double simp(double(*f)(double),double a,double b,int n)
{
  int i;
  double sum,ini,h;
  i=0;sum=0.0;ini=0.0;
  h=(b-a)/n;
  ini+=(*f)(a);
  ini+=(*f)(b);
  for(i=1;i<=n/2.0;i++)
	{
	  ini+=4*((*f)(a+((2*i)-1)*h));
	  ini+=2*((*f)(a+((2*i)-2)*h));
	}
  sum=(1.0/3.0)*h*ini;
  return sum;
}

int main()
{
  int i=10000;
  double a=0.0,b=M_PI/2.0;

  cout<<"The integral is "<<simp(func,a,b,i)<<endl;
  return 0;
}

But when I complied this code it shows -

In function ‘int main()’:
error: invalid conversion from ‘double (*)(double, double)’ to ‘double (*)(double)’
error: initializing argument 1 of ‘double simp(double (*)(double), double, double, int)’

I am a beginner in function pointer . So please suggest me how do I call the function to get rid of this error??

[carltech]

What are you trying to do? are you trying to pass a pointer or pass a function to the function?

if you want to pass a pointer then it should be double simp(double *f,double a,double b,int n)
Then you would have problems with the compiler thinking that you are using f as a function. ini+=(*f)(a); looks like a is being passed to f. if you meant to do multiplycation then use *.

If you meant to pass a function then myb.

[aries0152]

carltech, on 23 Sep, 2009 - 12:09 AM, said:

are you trying to pass a pointer or pass a function to the function?

I want to pass the function

[aks29921]

if a function has two parameters, you should always pass them to it, this was one mistake committed by you.
i have edited your code where necessary and put your wrong syntax inside comments.
here you go:

#include<iostream.h>
#include<math.h>

double func(double t,double f)
{
	return 1.0/sqrt(1.0-pow((sin(t/2.0)*sin(f)),2));
}

double simp(double(*f)(double,double),double a,double b,int n)
{
  int i;
  double sum,ini,h;
  i=0;sum=0.0;ini=0.0;
  h=(b-a)/n;
  ini+=f(a,b);
  for(i=1;i<=n/2.0;i++)
	{
	  ini+=4*(f(a+((2*i)-1),h));
	  //ini+=2*((*f)(a+((2*i)-2)*h));
	}
  sum=(1.0/3.0)*h*ini;
  return sum;
}

int main()
{
  int i=10000;
  double a=0.0,b=M_PI/2.0;

  cout<<"The integral is "<<simp(func,a,b,i)<<endl;
  return 0;
}

this program compiles and runs properly..
the output may not be what you desire, that's because i have not tried to understand what you are doing but have just corrected your syntax in certain places.
you can build on this code to do exactly what you want...

This post has been edited by aks29921: 23 September 2009 - 03:03 AM

[aries0152]

Error solved. Thank you

[NickDMax]

nice job aks29921