[vishalpiratla]

import java.util.Scanner; 

public class tempconverter {


	
	 
	public static void main(String[] args) {
		final int Base = -32;  
		final double CONVERSION_FACTOR = 5.0 / 9.0;
		int farenheit;
		int CelsiusTemp;
		
		Scanner scan = new Scanner (system.in);		
		System.out.print("Enter the farenheit temperature: ");
		farenheit = scan.nextInt();
		
		CelsiusTemp = farenheit * CONVERSION_FACTOR + Base; 
		
		System.out.println("Celsius Equivalent: " + CelsiusTemp);
	}

}

[KYA]

Put your question in the body of the post please.

[vishalpiratla]

KYA, on 18 Nov, 2009 - 06:04 PM, said:

Put your question in the body of the post please.

sorry im still getting used to this site. but when I try to run this code i keep getting this error: Exception in thread "main" java.lang.Error: Unresolved compilation problems:
system cannot be resolved
Type mismatch: cannot convert from double to int

at tempconverter.main(tempconverter.java:14)
and i have no clue how to resolve it

[pbl]

CelsiusTemp = farenheit * CONVERSION_FACTOR + Base;

CelsiusTemp is an int
CONVERSION_FACTOR a double

In Java if the left side of a = contains one double variable all operations are "upgraded to double

you cannot put a double into a int

let say:

int x;
double y = 1.0E100;

x = y; // you cannot store 1000000000000000000000...00000 a hundred times into a int

now if you know for sure that your double is convertibele to a int (behing in the int range) you can always cast

CelsiusTemp = (int) farenheit * CONVERSION_FACTOR + Base;

[vishalpiratla]

pbl, on 18 Nov, 2009 - 07:06 PM, said:

CelsiusTemp = farenheit * CONVERSION_FACTOR + Base;

CelsiusTemp is an int
CONVERSION_FACTOR a double

In Java if the left side of a = contains one double variable all operations are "upgraded to double

you cannot put a double into a int

let say:

int x;
double y = 1.0E100;

x = y; // you cannot store 1000000000000000000000...00000 a hundred times into a int

now if you know for sure that your double is convertibele to a int (behing in the int range) you can always cast

CelsiusTemp = (int) farenheit * CONVERSION_FACTOR + Base;

vishalpiratla, on 19 Nov, 2009 - 12:49 PM, said:

pbl, on 18 Nov, 2009 - 07:06 PM, said:

CelsiusTemp = farenheit * CONVERSION_FACTOR + Base;

CelsiusTemp is an int
CONVERSION_FACTOR a double

In Java if the left side of a = contains one double variable all operations are "upgraded to double

you cannot put a double into a int

let say:

int x;
double y = 1.0E100;

x = y; // you cannot store 1000000000000000000000...00000 a hundred times into a int

now if you know for sure that your double is convertibele to a int (behing in the int range) you can always cast

CelsiusTemp = (int) farenheit * CONVERSION_FACTOR + Base;

thanks man that was really helpful. now I am encountering another problem. My program runs but its not giving me the correct answer. for example when i enter 32 degrees Fahrenheit i get a response of -14 degrees Celsius. i fiddled around with the code to make it work but i couldnt figure it out. here is the updated code, see if anyone can figure out where i am going wrong.

import java.util.Scanner; 

public class tempconverter {


	
	 
	public static void main(String[] args) {
		final int Base = -32;  
		final double CONVERSION_FACTOR = 5.0 / 9.0;
		int farenheit;
		double CelsiusTemp;
		
		Scanner scan = new Scanner (System.in);		
		System.out.print("Enter the farenheit temperature: ");
		farenheit = scan.nextInt();
		
		CelsiusTemp = (int)farenheit * CONVERSION_FACTOR + Base; 
		
		System.out.println("Celsius Equivalent: " + CelsiusTemp);
	}

}

[pbl]

This formula is wrong

farenheit * CONVERSION_FACTOR + Base

the Base should be multiply by 5
the original formula is

C / 5 = (F - 32) / 9
so
C = (F - 32) / 9 / 5

the Base should be subtract before the CONVERSION_FACTOR is applied