[bluesuus]

write a program that counts the number of occurence of he operator( != ) in a given c++ program file.

[Mrafcho001]

Aren't you getting tired of making quizes, that no one does anymore?

//Have read the entire file in to a string
//str contains the the file
size_t pos = 0;
int numofOccurance = 0;
while(pos != string::npos)
{
pos = str.find("!=", pos+1);
if(pos != string::npos)
{
numofOccurance++;
}
else
{
break;
}
//numofOccurance now contains the number of times != occurs in the string

[Jessehk]

How do I know this isn't a homework question?

[Mrafcho001]

It probably is

[bluesuus]

HI guys, i cn c that u think i giv u guys my homework, well dats nt true, i cn do way better than that.and of course some of the solutions i give dem myself.i have finished this course with an A+.?im way pass that...neway i jus thot it cud be kinda kuul, to hv problems that will make u feel gud about urself.

back to the quiz...mrafcho i think ur program does count only the first != operator it sees always, if there are many it doesnt count them all.

i believe if u take the content character by charater it makes more sense.
example

in.open("text.txt");
in.get(prevchar);
in.get(currchar);

while( in )
{
if ( prevchar == '!' && currchar == '=' )
count++;

prevchar = currchar;

in.get(currchar);
}

okay guys this is it, the last quiz.....I will like to take some time and thank all the people that participated in all the quizez i posted...mrafcho in particular for solvn almost all tha problems, wekk done...Adios guys

[Mrafcho001]

Nope, it works fine. I guess you should learn the string class.

Tested

This post has been edited by Mrafcho001: 09 January 2006 - 09:10 PM