[rms7936]

I am making a very simple code for a flowchart.
I am encountering a brain block though.

import java.util.Scanner;

public class exam {

	
	public static void main(String[] args) {
		Scanner reader = new Scanner(System.in);
		boolean answer1;
		String answer2;
		String answer3;
		
		System.out.println ("Are you Christian?");
		answer1 = reader.next();
		if (answer1);
	}

}

I am running into errors with the "answer1 = reader.next();"
How do i make it so it reads for Boolean? It isn't as of now.
I know this is very simple and i appreciate any of you who take the time to help me.

[macosxnerd101]

You can use the Scanner nextBoolean() method to do so.

[Dogstopper]

reader.nextBoolean() should do the trick. Reading API's do wonders...
Here's a link: http://java.sun.com/...il/Scanner.html

EDIT: wow THREE people?!

This post has been edited by Dogstopper: 11 January 2010 - 07:30 PM

[erik.price]

Scanner has a nextBoolean() method which would probably be what you're looking for.

http://java.sun.com/...l#nextBoolean()

edit: ahh. you both beat me to it

This post has been edited by erik.price: 11 January 2010 - 07:30 PM

[rms7936]

Thanks all. Sorry for the simple question. Thanks for the links.

[erik.price]

No problem.

By the way, your signature made me laugh

[Simple_Condolences]

reader.nextBoolean();

and

reader.nextLine();

will both work. nextLine will require a more involved if statement though, just a heads-up.

[rms7936]

I can't get the if statement to work now...
I seriously can't think tonight.
What am I supposed to do with it?

[Dogstopper]

When comparing strings, remember to always use the .equals method when comparing strings!

if (answer.equals("The Answer))

EDIT: DOH...what did I smoke!

This post has been edited by Dogstopper: 11 January 2010 - 09:49 PM

[rms7936]

Dogstopper, on 11 Jan, 2010 - 08:39 PM, said:

When comparing strings, remember to always use the .equals method when comparing strings!

if (answer.equals("The Answer))

"Cannot invoke equals(String) on primitve type boolean"
i get this error

[Dogstopper]

Absolutely right! I was SO WRONG ON THAT. Sorry. When entering the answer, you must type "true" or "false", and in the if statement, do this:

if (answer)
	System.out.println("Something");
else
	System.out.println("Other stuff);

This post has been edited by Dogstopper: 11 January 2010 - 10:02 PM

[rms7936]

Dogstopper, on 11 Jan, 2010 - 08:48 PM, said:

Absolutely right! I was SO WRONG ON THAT. Sorry. When entering the answer, you must type "True" or "False", and in the if statement, do this:

if (answer)
	System.out.println("Something");
else
	System.out.println("Other stuff);

Thank you again!
I think I've got it all figured out now.
-sigh-
All this effort for some measly extra credit.

import java.util.Scanner;

public class exam {

	
	public static void main(String[] args) {
		Scanner reader = new Scanner(System.in);
		boolean answer1;
		String answer2;
		String answer3;
		
		System.out.println ("Are you Christian?");
		answer1 = reader.nextBoolean();
		boolean yes = false;
		if (answer1 == yes)
			System.out.println("Fail");
		else
			System.out.println("next question");
	}

}

I get this message:
Exception in thread "main" java.util.InputMismatchException
at java.util.Scanner.throwFor(Unknown Source)
at java.util.Scanner.next(Unknown Source)
at java.util.Scanner.nextBoolean(Unknown Source)
at exam.main(exam.java:13)

[Dogstopper]

Look at me! made ANother typo! It has been fixed. Make sure when you turn it in to type it exactly like that. Now it works for me!

[pbl]

Nver tried nextBoolean() on a Scanner
what is a valid boolean input: "T", "F", 'true", "false", "True", "False", "TRUE", "FALSE" ?
Better to read a String (scanner.next()) if check if the first character of the String is "Y" or "N" ignoring the case

[Simple_Condolences]

import java.util.Scanner;

public class exam {

   
	public static void main(String[] args) {
		Scanner reader = new Scanner(System.in);
		boolean answer1;
		String answer2;
		String answer3;
	   
		System.out.println ("Are you Christian?(y/n): ");
		answer1 = reader.nextLine();
		if (answer1.equalsIgnoreCase("y"))
		   //insert what it needs to do if true
		else
		  //insert what to do if false
	}

}

My head hurts too much from working on my stuff to really think of a way to explain it without just typing the code so here's a freebie.

- Zach