[Elvang]

How would I initialize a variable-sized array to all '0's/'false's in C++? I know I can just use a for loop to iterate over the array, but I'd rather know why I can't initialize it like non variable-sized objects.

// Bare minimum to generate compiler error:
// variable-sized object `array' may not be initialized
#include <iostream>

int main(int argc, char** argv) {
	bool array[argc] = {false};
	// bool array[17] = {false}; // Legal
	return 0;
}

PS: I currently make sure it won't try to create a size 0 array, but what would happen if it did attempt to?

[pdkharkar]

if you declare the array as static all elements are initialized to zero

but I am not sure
please check it

[Elvang]

Declaring it static causes the compiler to list the following errors in addition to the previous error:

• storage size of `array' isn't constant
  
• size of variable 'array' is too large

[jjl]

memset

char arr[20];
//initialize all to NULL
memset(arr,'\0',sizeof(arr));

//*****
int arr[20;
//initialize all to zero
memset(arr,0,sizeof(arr));

This post has been edited by ImaSexy: 25 January 2010 - 06:53 PM

[ubunta]

Elvang, on 25 January 2010 - 06:33 PM, said:

Declaring it static causes the compiler to list the following errors in addition to the previous error:

• storage size of `array' isn't constant
  
• size of variable 'array' is too large

also it will not work for float arrays

[indelako]

you need to make the data type of the array and the size of it. if you want, you can also initialize the content of the array.

Example:

char name[2]={"del" , "danny" };
it us not allowed that your array size is less that what you initialized

[macosxnerd101]

Please avoid necroposting. Topic closed.