[Tapas Bose]

Here it is :

#include <iomanip>
#include <iostream>

using namespace std;

int main()
{
   int column, ctr, column_ctr;
   char ch;

   while (ctr = 1)
   {
      cout << endl;
      cout << "Number of column: ";
      cin >> column;
      cout << endl;

      if (column == 0)
      {
         return 0;
      }

      else if (column==1)
      {
         for (ch='A'; ch<='O'; ch++)
         {
            cout << setw (9) << ch << endl;
            cout << endl;
         }
      }

      else if (column == 2)
      {
         int counter = 0;
         for (ch='A'; ch<='O'; ch++)
         {
            cout << setw (9) << ch;
            counter++;
            if (counter == 2)
            {
               cout<<endl;
               counter=0;
            }
         }        
       }

      ctr++;
   }

   return 0;
}

This post has been edited by Tapas Bose: 22 March 2010 - 10:15 AM

[diego_pmc]

In the for-loop for two columns you have no line break (endl) anywhere. You need to break the line after you print two characters. One way to do that is to print the character, increment it, print it again, and then break the line (all of this should happen in the for loop):

for (char ch = 'A'; ch <= 'O'; ch++) {
    cout << setw(9) << ch;
    if ((ch + 1) <= 'O')
        cout << setw(9) << ++ch;
    cout << endl;
}

This post has been edited by diego_pmc: 22 March 2010 - 10:25 AM

[sarmanu]

A simpler method would be to check if the loop counter (converted to int) is even:

else if (column==2)
{
	for (ch='A'; ch<='O'; ch++)
	{
                // actually is ch + 1 for your desired output
                // since A "integered" is 65
		if (int(ch + 1) % 2 == 0)
			cout << endl;
		cout << setw (2) << ch;
	}
	cout << endl << endl;
}

[LiveToCode]

Another solution is

for (int k = 1; k < 10; k++) {
   cout<<k <<" ";
   if (k % 2 == 0)
      cout<<endl;
}

That will print the numbers in 2 columns. You can modify the 2 in the if statement to the number of columns you want.

[jjl]

I think a single for loop can get the job done dont you think?

#include <iostream>

using namespace std;

int main()
{
	int count = 0;
	for(char i = 'a'; i<='z'; i++)
	{
		count++;
		cout<<i;
		if(count%2 == 0)
			cout<<endl;
	}
	
	cin.ignore();
	cin.get();
	return 0;
}

[diego_pmc]

And also...

while (ctr=1)

... I guess you meant one of these...

while (ctr == 1)
// or...
while (ctr != 1)

This post has been edited by diego_pmc: 22 March 2010 - 10:26 AM