[angelofdzire]

I am having a difficult time passing the value from one function to another. I've rewritten this program so many times... that before I pulled any more hair out ( ) I wanted to see if I can get some constructive feedback.
In my program, I am asking for the user to input a string, then pass that string to the getLength function, and then display the functions return value. However, if I did cin before referencing the getLength function, it would tell me invalid conversion. Even if I changed the parameter type to match, I am still getting the same error messages.
Now in the getLength function, I know I need to return some value... what I have in there now I know doesn't work, it's just showing that I understand I need to return some value back to the main function.
Can someone please point me in the right direction?
Thank you =)

#include <iostream>
using namespace std;

int *getLength(int);

int main()
{
    int townLength;
    int *ptr;
     
    cout << "Enter your towns name.\n";
    
    getLength(townLength);
    
    ptr = getLength(townLength);
    cout << "Your town has" <<  ptr << "characters" << endl;
    
    delete [] ptr;
    ptr = 0;
    system ("PAUSE"); 
      
    return 0;
}
//*********************************************
// Function nameLength                        *
// This function counts the number of         *
// characters in a string.                    *
//                                            *
//*********************************************



int *getLength(int)
{
   string townName;
   int *ptr;

   cin >>townName;  //Read as a string
    
   ptr = townName.size();
   
   return ptr;
    
}

[JackOfAllTrades]

int *getLength(int)
{
   string townName;
   int *ptr;

   cin >>townName;  //Read as a string
    
   ptr = townName.size();
   
   return ptr;
}

For starters, the size() method of a string object does NOT return a pointer to an integer, it returns a size_t. Why do you need to pass an argument at all? You're not using it; in fact, you're not even giving it a name?

EDIT: How about reading our tutorial on functions?

This post has been edited by JackOfAllTrades: 28 March 2010 - 04:12 PM

[jjl]

like jack said, why even pass in a variable. You should refresh yourself on pointers too.

heres what would make sense

int *getLength(void)
{
	int *nameSize = new int; //so memory does not go out of scope
	string townName;
	cin>>townName;
	*nameSize = townName.length();
	return nameSize;
}