[punksryan]

import java.util.Scanner;
public class BinarytoDecimal {

    public static void main(String[] args) throws Exception {
      Scanner br = new Scanner(System.in);
        System.out.println("Enter the binary value:");
         String s = br.nextLine();
        System.out.println("Decimal value is : "+Integer.parseInt(s, 2));

    }
}

i want to study this program coz it is related to our subject in logsign... i wish you can help me guys...

[g00se]

What's the problem?

[eZACKe]

Doesn't seem to be a problem to me. You say you want to study the program, so are you asking what's happening?

I'll write comments on exactly what's happening:

import java.util.Scanner;//import Scanner for use with input
public class BinarytoDecimal {

    public static void main(String[] args) throws Exception {
      Scanner br = new Scanner(System.in);//Scanner class used to get input
        System.out.println("Enter the binary value:");//prints this message on screen
         String s = br.nextLine();//set s equal to whatever the user inputs
        System.out.println("Decimal value is : "+Integer.parseInt(s, 2));
        //^print out "Decimal value is : " + the string the user inputted,
        //parsed to a decimal value. The second parameter is the radix

    }
}

[macosxnerd101]

Please post your question in the body of your post, not in the title where it gets truncated. As Integer.parseInt() returns an int, no decimal point will be shown. However, you can cast it to a double, which will convert it to a floating-point number, or a very close representation to a real number (meaning that 1.41 might be represented as 1.4019999999999).

[DillonSalsman]

I'm not sure what you're asking either.
But if your curious as to how the value goes from base 2 to base 10, take a look at the src of the parseInt method.


Humans do something along the following:
For each digit n starting from the right, multiple the value of the digit by the base to the n-1 power.
Add these results together and you get base-10.

For example 11010101 would be
1 * 2^0 = 1
0 * 2^1 = 0
1 * 2^2 = 4
0 * 2^3 = 0
1 * 2^4 = 16
0 * 2^5 = 0
1 * 2^6 = 64
1 * 2^7 = 128
-----------
11010101 = 213

so to do base 16 [hexadecimal]
Instead of 0123456789 10 11 12 13 14 15
We use 0123456789ABCDEF

03FA to decimal is:
A [10] * 16^0 = 10
3 [03] * 16^1 = 48
F [15] * 16^2 = 3840
0 [00] * 16^3 = 0
-----------------
0F3A = 3898

This post has been edited by DillonSalsman: 21 June 2010 - 04:22 PM