#include<stdio.h> #include<math.h> #include<string.h> int bin2dec(int decimal); int main(void) { int num; printf("The decimal equilavent is: %d", bin2dec(decimal)); getchar(); getchar(); return 0; } int bin2dec(int decimal) { int num[10]; int i; int bin; int arr1[10]; int arr2[10] = {512,256,128,64,32,16,8,4,2,1}; printf("Enter a binary(0's and 1's) number: "); scanf("%d", &arr1); This is qheere I get confused. for (i = 0; i < arr1; i++) { if (arr1[i] == 1) num[i] = arr1[i]; arr2[i]= num[i] decimal = arr2[i]; } return decimal; }
Converting Binary to Decimal
Page 1 of 112 Replies  11895 Views  Last Post: 20 September 2010  09:01 PM
#1
Converting Binary to Decimal
Posted 24 September 2006  01:04 PM
Replies To: Converting Binary to Decimal
#2
Re: Converting Binary to Decimal
Posted 24 September 2006  09:46 PM
#3
Re: Converting Binary to Decimal
Posted 25 September 2006  01:02 AM
http://code.dreaminc...t/snippet30.htm
be aware that this takes binary in the form of righttoleft, meaning that the decimal value 2 is represented as 01.
whereas the lefttoright form would represent 2 as 10
#4
Re: Converting Binary to Decimal
Posted 25 September 2006  06:28 AM
int i, ch; printf("Enter an integer: "); scanf("%c",&ch); for(i=0x80; i;i=i>>1) printf("%d", ( (ch&i) ? 1 : 0 ) );
You can also use the itoa function to do this.
/* i is the number to be converted c is the buffer (char[]) where the binary number is stored. 2 represents the base which the source (ie. i ) has to be converted into. */ itoa(i,c,2); printf("%s",c);
If you can see something in the Previous code that used the For loop, you will see the possibility of using a recursive function to do this.
#5
Re: Converting Binary to Decimal
Posted 25 September 2006  07:54 AM
I am new so somethings seems difficult than they are.
This post has been edited by Dark_Nexus: 25 September 2006  08:46 AM
#6
Re: Converting Binary to Decimal
Posted 25 September 2006  05:05 PM
#include "stdafx.h" #include <stdio.h> #include<math.h> int bin2dec(int decimal); int main() { int decimal; printf("Enter an integer: "); scanf_s("%c",&decimal); printf("The decimal equivalent = %d\n",bin2dec(decimal)); getchar(); getchar(); return 0; } int bin2dec(int decimal) { int total = 0; int power = 1; while(decimal > 0) { total += decimal % 10 *power; decimal = decimal / 10; power = power * 2; } return decimal; }
This post has been edited by browngod2002: 25 September 2006  05:15 PM
#7
Re: Converting Binary to Decimal
Posted 25 September 2006  05:59 PM
scanf_s("%d",&decimal);
It would be of great benefit if you describe in what way your application is not working, so that someone can better help you.
List error messages, incorrect output, compilation errors.
#8
Re: Converting Binary to Decimal
Posted 26 September 2006  03:05 AM
snippet...... switch(choise) { case 1: cout << "Enter a Hex number: "; cin >> hex >> number; cout << "\n value in octal = " << oct << number << endl; cout << " value in decimal = " << dec << number << endl; break; case 2: cout << "Enter a Octal number: "; cin >> oct >> number; cout << "\n value in hex = " << hex << number << endl; cout << " value in decimal = " << dec << number << endl; break; case 3: cout << "Enter a dec number: "; cin >> dec >> number; cout << "\n value in octal = " << oct << number << endl; cout << " value in hex = " << hex << number << endl; break; case 4: cout << "Program terminated by user..."; exit(0); default : cout << "ERROR ~ Invalid selection\n\n"; break; }
If there arn't any objections I can put the compelted code up if you wish.
This post has been edited by Vagabond: 26 September 2006  03:17 AM
#9
Re: Converting Binary to Decimal
Posted 26 September 2006  11:49 AM
#include "stdafx.h" #include <stdio.h> #include <math.h> /* function prototype */ int bintodec(int decimal); int _tmain(int argc, _TCHAR* argv[]) { int decimal; printf("Enter an interger (0's and 1's): "); scanf_s("%d", &decimal); printf("The decimal equilavent is %d.\n", bintodec(decimal)); getchar(); getchar(); return 0; } int bintodec(int decimal) { int total = 0; int power = 1; int number = 0; decimal; while(decimal >=0) { /* this is where the problem is I need some advice on how to fix it.*/ total += decimal % 10 * power; decimal = decimal / 10; power = power * 2; number += decimal; decimal; } return number; }
This post has been edited by Dark_Nexus: 26 September 2006  09:54 PM
#10
Re: Converting Binary to Decimal
Posted 26 September 2006  11:54 AM
#11
Re: Converting Binary to Decimal
Posted 26 September 2006  03:50 PM
#include "stdafx.h" #include <stdio.h> #include <math.h> /* function prototype */ int bintodec(int decimal); int _tmain(int argc, _TCHAR* argv[]) { int decimal; printf("Enter an interger (0's and 1's): "); scanf_s("%d", &decimal); printf("The decimal equilavent is %d.\n", bintodec(decimal)); getchar(); getchar(); return 0; } int bintodec(int decimal) { int total = 0; int power = 1; while(decimal > 0) { total += decimal % 10 * power; decimal = decimal / 10; power = power * 2; } return total; }
This post has been edited by browngod2002: 26 September 2006  03:52 PM
#12
Re: Converting Binary to Decimal
Posted 20 September 2010  08:54 PM
#13
Re: Converting Binary to Decimal
Posted 20 September 2010  09:01 PM
#include <iostream> #include <math.h> using namespace std; int bin, decimal = 12, decimal2; int base_one = 10, base_two = 2; int convert(int num, int starting_base, int destination_base); int main (int argc, char * const argv[]) { bin = convert(decimal, base_one, base_two); cout << "Base"<< base_one<< " "<< decimal << " = Base"<< base_two<< " " << bin << endl; decimal2 = convert(bin, base_two, base_one); cout << "Base"<< base_two << " " << bin << " = Base"<< base_one << " " << decimal2 << endl; return 0; } int convert(int num, int starting_base, int destination_base) { int val = 0, count = 0; while (num) { val += pow(starting_base, count) * (num % destination_base); count++; num /= destination_base; } return val; }
