[Sahib28]

Code for swapping values without using third variable ..?
please help

[bhandari]

here is the logic:

a=10;
b=5;
a = a + b; ==> a=15
b = a - b; ==> b=10
a = a - b; ==> a=5

Simple isn't it?

[Sahib28]

bhandari, on 27 January 2011 - 11:27 AM, said:

here is the logic:

a=10;
b=5;
a = a + b; ==> a=15
b = a - b; ==> b=10
a = a - b; ==> a=5

Simple isn't it?

ya indeed it was .
thanks for the help.

[Dogstopper]

There is another way to do this using bits and XOR operator. It's also the same operation all three times, so it's simpler to remember:

a = a^b (^ is XOR)
b = a^b
a = a^b

[mostyfriedman]

I prefer the XOR method since with addition there is a chance for overflows.