[YBang]

Hi


What does this code snippet do?

long sin=234567890;
while (sin > 0) {
cout << sin % 10 << endl;
sin /= sin;
}

[newclearner]

What does your logic say about it?

[macosxnerd101]

Have you even run the code?

[YBang]

I'm kinda clueless hehe

I ran the code, its outputting 1 forever

[macosxnerd101]

You probably want to divide sin by 10, not sin, to output each digit individually.

[YBang]

Thanks

[macosxnerd101]

Glad I could help!

[YBang]

Hey guys I'm really having trouble doing this assignment

#include <iostream>

using namespace std;

long sin;
char fsin[12];
char temp[12];
char outSin(sin){
    int i, k;
    sin = char fsin[12];
    for (i=0; i<12; i++) {
        k=11;
        temp [k] = fsin[i];
        if (k==4||k==7) {
                        temp [k] = "-";
                        k--;
                        }
        k--;
        }
        return temp;
        }
        
        
int main() {


cin >>sin;
while (sin > 0) {
cout<<sin % 10;
sin /= 10;
}
cout<<"Here is your SIN: ";
outSin();

cout<<endl;
system ("pause");
return 0;
}


        

This is my code (not so good)

and heres what I have to do:

Write a function that takes the SIN as a long (instead of a character array) as its first parameter. It must have a character array as a second parameter. The character array will hold the formatted sin number. You may count on the fact that the SIN will always have 9 digits (100000000 to 999999999).

Input: ######### 9 numbers
Output: ###-###-###

any feedback would be great
Currently working on the errors I'm getting

one of the says outSin cannot be used as a function

This post has been edited by YBang: 11 February 2011 - 12:40 AM

[chinchang]

char outSin(sin){
// your code
}

You need to define a data type for the function parameter sin.

Also you are returning a char array not a character as your return type says. It should be char[]

Correct code:

char[] outSin(double sin){
// your code
}

I suggest you go over this tutorial by JackOfAllTrades.

This post has been edited by chinchang: 11 February 2011 - 02:01 AM