[polens]

Hey guys...
im self studying php because it is not offered in out school...
This is my first time...

<?php 
$aged= 100;
$age=  $_Post["Age"]; 

if ( $_POST["age"] > $aged)
  echo "Invalid Input!";
else
 
?>

Error:
Notice: Undefined variable: _Post in C:\xampp\htdocs\MyProject\FirstPhp\Welcome.php on line 6
Invalid Input!

how can i get the inputed data to a variable?

i manage to solved it thanks for viewing

[CTphpnwb]

PHP is case sensitive.
$_POST != $_Post

[e_i_pi]

[quote name='polens' date='13 February 2011 - 08:47 AM' timestamp='1297612073' post='1250031']
Try this:

<?php 
$aged = 100;
$age =  (int)$_POST["Age"]; 

if ($age > $aged)
{
  echo "Invalid Input!";
} else {
  // The rest of your code here
} 
?>

[Dormilich]

of course you should also check, if the POST array is already populated. if the PHP page is the same that outputs the according HTML, you won’t get anything on initial page load.

if (!isset($_POST['Age']))
{
    echo "no input given";
    // exit;
    // throw new Exception("first load.");
}